Where is the grid are u gonna take a pic?
Sounds like "formulas"! y = ax^2 + bx + c involves the variable x and the constants {a, b, c}. The "2" indicates "squaring function."
Answer:
The relation is not a function
The domain is {1, 2, 3}
The range is {3, 4, 5}
Step-by-step explanation:
A relation of a set of ordered pairs x and y is a function if
- Every x has only one value of y
- x appears once in ordered pairs
<u><em>Examples:</em></u>
- The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
- The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
- The domain is the set of values of x
- The range is the set of values of y
Let us solve the question
∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}
∵ x = 1 has y = 3
∵ x = 2 has y = 3
∵ x = 3 has y = 4
∵ x = 2 has y = 5
→ One x appears twice in the ordered pairs
∵ x = 2 has y = 3 and 5
∴ The relation is not a function because one x has two values of y
∵ The domain is the set of values of x
∴ The domain = {1, 2, 3}
∵ The range is the set of values of y
∴ The range = {3, 4, 5}
Answer:
9801
Step-by-step explanation:
Given the general term for calculating the nth term of a sequence;
Sn = n²
Where n is the number of terms.
To find the 99th term of the sequence using the nth term of the sequence;
Since we want to get the 99th term, this means that n = 99. Substituting n = 99 into the formula we will have;
S99 = 99²
S99 = 9,801
First find a common denominator
1/16(2/2) = 2/32
9/32 - 2/32 = 7/32
7/32 is your answer
hope this helps
