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katen-ka-za [31]
3 years ago
13

How many moles are in 22 grams of N2O?

Chemistry
1 answer:
raketka [301]3 years ago
4 0

Answer:

<h3>0.4998545877562891</h3>

Explanation:

<h3>#hopeithelps</h3><h3>stay safe and keep well</h3><h3 /><h3>can you mark me as your brainliest pls</h3>
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What is the mass of 1 mole in<br> ZnCl2
DENIUS [597]

Answer:

136.286 g/mol

Explanation:

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4 0
3 years ago
How many protons and neutrons does nitrogen-14 have?
zhenek [66]

Answer:

7 protons

Isotopes are atoms that have the same number of protons but different numbers of neutrons in the nucleus. You know that nitrogen-14 has 7 protons in the nucleus because it is an isotope of nitrogen, which has an atomic number equal to 7 .

4 0
4 years ago
How does electronegativity cause the polarity in water and, ultimately, enable water to form hydrogen bonds between other water
gulaghasi [49]
Oxygen is more <u>electronegative</u> than Hydrogen 
                                  So . . . 
When the two form covalent bonds, oxygen pulls the electrons closer and farther from hydrogen
                                   So . . .
The water molecule is <u>polar</u>, with oxygen more negative and hydrogen more positive.
                                   So . . .
Since opposites attract, the more negative oxygens attract the more positive hydrogens of other water molecules, forming the <u>hydrogen bonds.</u>
6 0
4 years ago
0.055 grams of PbSO4 is dissolved in 200.00 grams of H2O.
Greeley [361]

Answer:

Solution's mass = 200.055 g

[PbSO₄] = 275 ppm

Explanation:

Solute mass = 0.055 g of lead(II) sulfate

Solvent mass = 200 g of water

Solution mass = Solvent mass + Solution mass

0.055 g + 200 g = 200.055 g

ppm = μg of solute / g of solution

We convert the mass of solute from g to μg

0.055 g . 1×10⁶ μg/ 1g = 5.5×10⁴μg

5.5×10⁴μg / 200.055 g = 275 ppm

ppm can also be determined as mg of solute / kg of solution

It is important that the relation is 1×10⁻⁶

Let's verify: 0.055 g = 55 mg

200.055 g = 0.200055 kg

55 mg / 0.200055 kg = 275 ppm

6 0
3 years ago
Let’s say we start with 2.2lbs of uranium. If the half-line of U-235 is 703.8 million years, how much uranium will we have after
oksian1 [2.3K]

Answer:

0.14 lb

Explanation:

The <em>half-life</em> of U-235 (703.8 ×10⁶ yr) is the time it takes for half the U to decay.  

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

We can construct a table as follows:

  No. of                        Fraction         Amount

<u>half-lives</u>  <u>t/(yr × 10⁶)</u>  <u>remaining</u>   <u>remaining/lb </u>

       1             703.8            ½                    1.1

       2           1408               ¼                   0.55

       3            2111                ⅛                   0.28

       4           2815               ¹/₁₆                  0.14

We see that 2815 × 10⁶ yr is four half-lives, and the amount of U-235 remaining is 0.14 lb.

6 0
3 years ago
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