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Olin [163]
3 years ago
14

Three beakers contain clear, colorless liquids. One beaker contains pure water, another contains salt water, and another contain

s sugar water. How can you tell which beaker is which? (No tasting allowed!)

Chemistry
2 answers:
gladu [14]3 years ago
6 0
Pure water may be identified by its density: it will have the lowwest density of the three solutions, given that the solutes (salt and sugar) increase the density (this is the easiests and quickest way).

You can also measure the freezing points or boling points to identify the pure water because the solutes depress the freezing points and increase the boling points.

To differentiate sugar water and salt water, you can probe which one conducts electricity, because salt water is a conductor (given that it ionizes into Na+ and Cl-) but sugar water is not a conductor.
Anastaziya [24]3 years ago
4 0

To differentiate the three solutions in a beaker, the electrode circuit test and direct current source and the heating process are used

<h3>Further explanation</h3>

Electric current in an electrolyte solution is caused by the ions that move between the electrodes with one another. So these ions are the conductor of electricity.

Electrical conductivity can be interpreted as the ability of a conductor in this case an electrolyte solution to move an electric charge

Electrical conductivity indicates an easy measure of whether or not a solution conducts an electric current.

Based on the electrical conductivity, electrolytes can be grouped into strong electrolytes and weak electrolytes

Liquid substances can be grouped based on their electrical conductivity, namely electrolyte and non-electrolyte solutions.

The sign of the solution is an electrolyte can be used a test equipment consisting of a series of electrodes and a direct current source. If the light is on, the solution is an electrolyte solution

Some substances in the solid state cannot conduct electricity but in a liquid / solution state can conduct electricity.

examples of strong electrolyte solutions: HBr, NaCl

Example of a weak electrolyte solution: CH₃COOH

Examples of non-electrolyte solutions:

Sugar Solution (C₁₂H₂₂O₁₁), Ethanol (C₂H₅OH), Urea (CO(NH₂)₂)

Of the three beaker water which is an electrolyte solution is a salt solution (NaCl), while water and sugar are not an electrolyte solution, so that when tested in a series of electrodes and direct current sources ,they cannot turn on the lights

Furthermore, to distinguish between water and sugar solution, the heating process can be carried out and the boiling point measured with a thermometer.

The boiling point of the sugar solution will be greater than water because there are sugar solutes

<h3>Learn more</h3>

colligative properties

brainly.com/question/8567736

Raoult's law

brainly.com/question/10165688

The vapor pressure of benzene

brainly.com/question/11102916

The freezing point of a solution

brainly.com/question/8564755

brainly.com/question/4593922

brainly.com/question/1196173

Keywords: Boiling Point, electrolyte solution

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puteri [66]

Answer:

See explanation

Explanation:

If the energy of the ground state E1 is known, then we need to measure the difference in energy between the energy levels E5 .and E1. We can obtain this by measuring the frequency or wavelength of a photon that is emitted when an electron moves from energy level E5 to E1.

From Bohr's model;

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7 0
2 years ago
1. Which of the following correctly represents a balance chemical equation? (a) NaCl + 2H2O → 2NaOH + 2Cl2 + H2 (b) 2NaCl+H2O →
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Answer:

thx sa points

Explanation:

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2 years ago
A 2.000 g sample of CoCl2.xH2O is dried in an oven. When the anhydrous salt is removed from the oven, its mass is 1.565 g. What
Mashutka [201]

The value of X is 2

The total amount of sample taken is 2.00 g

The amount of sample left in the oven after drying is 1.565g

The amount of sample lost (mass of water driven out) = Total sample-Anhydrous salt left in the oven

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The complete chemical reaction is   CoCl2.2H20

To know more about the Similar calculation and explanation click here:

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6 0
10 months ago
How many milliliters of a 0.40%(w/v) solution of nalorphine must be injected to obtain a dose of 1.5 mg?
ozzi
The number  of Ml  of  a  0.40 %w/v solution  of   ,nalorphine  that must  be injected  to  obtain  a  dose  of 1.5 mg is  calculated as  below


since M/v%   is  mass  of solute  in  grams per 100  ml

convert Mg to  g
1 g = 1000 mg  what  about  1.5 mg =?  grams
=   1.5 /1000 = 0.0015 grams


volume is therefore =  100 (  mass/ M/v%)

= 100  x(  0.0015/ 0.4) =  0.375  ML
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