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Olin [163]
3 years ago
14

Three beakers contain clear, colorless liquids. One beaker contains pure water, another contains salt water, and another contain

s sugar water. How can you tell which beaker is which? (No tasting allowed!)

Chemistry
2 answers:
gladu [14]3 years ago
6 0
Pure water may be identified by its density: it will have the lowwest density of the three solutions, given that the solutes (salt and sugar) increase the density (this is the easiests and quickest way).

You can also measure the freezing points or boling points to identify the pure water because the solutes depress the freezing points and increase the boling points.

To differentiate sugar water and salt water, you can probe which one conducts electricity, because salt water is a conductor (given that it ionizes into Na+ and Cl-) but sugar water is not a conductor.
Anastaziya [24]3 years ago
4 0

To differentiate the three solutions in a beaker, the electrode circuit test and direct current source and the heating process are used

<h3>Further explanation</h3>

Electric current in an electrolyte solution is caused by the ions that move between the electrodes with one another. So these ions are the conductor of electricity.

Electrical conductivity can be interpreted as the ability of a conductor in this case an electrolyte solution to move an electric charge

Electrical conductivity indicates an easy measure of whether or not a solution conducts an electric current.

Based on the electrical conductivity, electrolytes can be grouped into strong electrolytes and weak electrolytes

Liquid substances can be grouped based on their electrical conductivity, namely electrolyte and non-electrolyte solutions.

The sign of the solution is an electrolyte can be used a test equipment consisting of a series of electrodes and a direct current source. If the light is on, the solution is an electrolyte solution

Some substances in the solid state cannot conduct electricity but in a liquid / solution state can conduct electricity.

examples of strong electrolyte solutions: HBr, NaCl

Example of a weak electrolyte solution: CH₃COOH

Examples of non-electrolyte solutions:

Sugar Solution (C₁₂H₂₂O₁₁), Ethanol (C₂H₅OH), Urea (CO(NH₂)₂)

Of the three beaker water which is an electrolyte solution is a salt solution (NaCl), while water and sugar are not an electrolyte solution, so that when tested in a series of electrodes and direct current sources ,they cannot turn on the lights

Furthermore, to distinguish between water and sugar solution, the heating process can be carried out and the boiling point measured with a thermometer.

The boiling point of the sugar solution will be greater than water because there are sugar solutes

<h3>Learn more</h3>

colligative properties

brainly.com/question/8567736

Raoult's law

brainly.com/question/10165688

The vapor pressure of benzene

brainly.com/question/11102916

The freezing point of a solution

brainly.com/question/8564755

brainly.com/question/4593922

brainly.com/question/1196173

Keywords: Boiling Point, electrolyte solution

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Gnesinka [82]

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Its helium

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7 0
2 years ago
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A steam engine (assume a Carnot engine ) has an efficiency of 50.8%. If the waste heat has a temperature of 72.4 ◦C, what is the
Inessa05 [86]

Answer:

The temperature of the boiler is approximately 147.1 °C

Explanation:

A Carnot engine is an ideal engine that has the highest efficiency among all the engines because the second law of thermodynamics.That efficiency \eta  is:

\eta=1-\frac{T_{c}}{T_{h}}

with T_{h} the temperature of the hot reservoir (the boiler temperature) and T_{c} the temperature of the cold reservoir (the steam temperature). Solving for T_{h}:

T_{h}=\frac{-T_{c}}{\eta-1}=\frac{-72.4}{0.508-1}\approx147.1\,C

3 0
2 years ago
The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate
vovangra [49]

Answer:

K2 = 61.2 M^-1.S^-1

Explanation:

We complete the question fully:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0kJ/mol . If the rate constant of this reaction is 6.7M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

Answer is as follows:

The question asks us to calculate the value of the rate constant at a certain temperature, given that it is at a particular value for a particular temperature. We solve the question as follows:

According to Arrhenius equation, the relationship between temperature and activation energy is as follows:

            k = Ae^-(Ea/RT)

where,   k = rate constant

              A = pre-exponential factor

          Ea  = activation energy

             R = gas constant

              T = temperature in kelvin

From the equation, the following was derived for a double temperature problem:

ln(k2/k1) = (-Ea/R) * (1/T1 - 1/T2)

We list out the parameters as follows:

         

      T1= (244 + 273.15) K = 517.15 K

      T2= (324+ 273.15) K =597.15 K

    K1  = 6.7 ,     K2 = ?

         R = 8.314 J/mol K

     Ea = 71.0 kJ/mol = 71000 J/mol

Putting the given values into the above formula as follows:

ln(k2/6.7) = (-71000/8.314) * (1/517.15 - 1/597.15)

lnk2 - 1.902 = 8539.8 * 0.000259

lnK2 = 1.902 + 2.21

lnK2 = 4.114

K2 = e^(4.114)

K2 = 61.2

Hence, K2 = 61.2 (M.S)^-1

7 0
3 years ago
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Please help fast, I will give brainliest.
frez [133]

Answer:

The reaction is favorable at all temperatures

Explanation:

Since G = H - TS, -H and +S would result in G = -H -TS, which will always be negative.

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Which one of these are correct?
Sergio [31]

The correct answer is the one in the middle. Mixing food coloring and water

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