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Ksivusya [100]
2 years ago
15

What is the percent increase 41,700 and 63,00

Mathematics
1 answer:
valentinak56 [21]2 years ago
7 0

Answer:

51.0791%

Step-by-step explanation:

Calculate percentage change

from V1 = 41700 to V2 = 63000

(V2−V1)|V1|×100

=(63000−41700)|41700|×100

=2130041700×100

=0.510791×100

=51.0791%change

=51.0791%increase

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The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or
tigry1 [53]

<u>Answer-</u>

<em>The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%</em>

<u>Solution-</u>

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

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P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}


P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67

Putting these values,

P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%

5 0
3 years ago
What’s the reciprocal of 5 4/9
stealth61 [152]

Answer:

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Step-by-step explanation:

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5 0
1 year ago
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