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NeTakaya
3 years ago
11

HELP I NEED THIS DONE QUICKK CAN ANNYONE HELP???????????????????????????????????????????????????????????????????????????????????

?????????????????????????????????????????????????????????

Mathematics
1 answer:
natulia [17]3 years ago
6 0
For the first question, it would be D: \frac{1}{3} ÷ 9. This is because to solve a division problem with fractions, you would need to multiply the first fraction by the reciprocal of the second fraction. For the second question, the answer would be D: 32. This can be solved by dividing 8 by \frac{1}{4} or 0.25. For the third question, it would be D. \frac{1}{12}. This can be solved by dividing \frac{1}{4} by 3. For the fourth question, the answer would be \frac{1}{12}. This can be found by flipping the 4, which would make it look like \frac{1}{4}, and multiplying it by \frac{1}{3}. For the last question, 1 would be B, 2 would be C, 3 would be C, and 4 would be A.

Hope this helps ^-^
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PLEASE ANSWER HONESTLY (PLEASE BE HELPFULL I HAVE BEEN STUCK ON THIS PROBLEM) WILL MARK BRANIEST IF CORRECT. (no links my comput
motikmotik

Step-by-step explanation:

o2+a2=h2

100} h^{2}=(10ft)^{2} +(17ft)^{2}

h2=100ft2+289ft2

h=389ft2−−−−−√

→19.7ft

this is an example on how to do it

8 0
2 years ago
NEED HELP ASAP WILL GIVE BRAINLIEST
AleksandrR [38]
I must assume that your graph is that of a straight line, and that the end points of the line are P and B, and (finally) that T is between P and B.  If these assumptions are correct, then the length of the line segment PB connecting points P and B is 15 + 10, or 25.
5 0
3 years ago
The minimum/maximum value of the function y = a(x − 2)(x − 1) occurs at x = d, what is the value of d?
daser333 [38]

Answer:

d=\frac{3}{2}=1.5

Step-by-step explanation:

We have the function:

y=a(x-2)(x-1)

And we want to find x=d for which the minimum/maximum value will occur.

Notice that our function is a quadratic in factored form.

Remember that the minimum/maximum value always occurs at the vertex point.

And remember that the x-coordinate of the vertex is the axis of symmetry.

Since a quadratic is always symmetrical on both sides of its axis of symmetry, a quadratic’s axis of symmetry is the average of the two roots/zeros of the quadratic.

Therefore, the value x=d such that it produces the minimum/maximum value is the average of the two roots.

Our factors are <em>(x-2) </em>and <em>(x-1)</em>.

Therefore, our roots/zeros are <em>x=1, 2</em>.

So, the average of them are:

d=\frac{1+2}{2}=3/2=1.5

Therefore, regardless of the value of <em>a</em>, the minimum/maximum value will occur at <em>x=d=1.5</em>.

Alternative Method:

Of course, we can also expand to confirm our answer. So:

y=a(x^2-2x-x+2)\\y=a(x^2-3x+2)\\y=ax^2-3ax+2a

The x-coordinate of the vertex is still going to be the place where the minimum/maximum is going to occur.

And the formula for the vertex is:

x=-\frac{b}{2a}

So, we will substitute <em>-3a</em> for <em>b</em> and <em>a</em> for <em>a</em>. This yields:

x=-\frac{-3a}{2a}=\frac{3}{2}=1.5

Confirming our answer.

4 0
3 years ago
HELP ME FAST PLZ ❗️.
vfiekz [6]

Answer:

8

Step-by-step explanation:

You use law of sines, and get: AB/sin(53) = 7/sin(44)

You multiply both sides by sin(53), and get:

AB = 7*sin(53)/sin(44)

That means AB is 8.04776679886, which rounds to 8

7 0
3 years ago
HELP ME Using the following equation, complete the square and find the center and radius of the circle:
IrinaK [193]

Answer: (-2,3), r=5\ \text{units}

Step-by-step explanation:

Given

the equation is x^2+y^2+4x-6y-12=0

completing the square

\Rightarrow (x^2+2\times 2\times x+4-4)+(y^2-2\times3\times y+9-9)-12=0\\\Rightarrow (x^2+2\times 2\times x+4)+(y^2-2\times3\times y+9)-12-4-9=0\\\Rightarrow (x+2)^2+(y-3)^2=25\\\Rightarrow (x+2)^2+(y-3)^2=5^2\\\Rightarrow (x-(-2))^2+(y-3)^2=5^2

Thus, the center of the circle is (-2,3) and radius is r=5\ \text{units}

5 0
3 years ago
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