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Gala2k [10]
3 years ago
6

Solve the equations. a. (x − 2)^2 = 9 b. 3(x − 2)^2 = 9 c. 6 = 24(x + 1)^2

Mathematics
1 answer:
seropon [69]3 years ago
4 0

Answer: a) x = 5 or -1 b) x = √3+2

c) x = -1/2 or -3/2

Step-by-step explanation:

a) (x − 2)² = 9

First step is to take the square root of both sides to eliminate the square

√ (x − 2)² = √9

x-2 = +-3

x = +3+2

x = 5 and;

x = -3+2

x = -1

x = 5 or -1

b) 3(x-2)² = 9

First we divide both sides by 3 to get;

(x-2)² = 9/3

(x-2)² = 3

Second step is to take the square root of both sides to eliminate the square

√(x-2)² = √3

x-2 = √3

x = √3+2

c) 6 = 24(x+1)²

Dividing both sides by 24, we have

6/24 = (x+1)²

1/4 = (x+1)²

Taking the square root of both sides we have

√1/4 = √(x+1)²

= +-1/2 = x+1

x = +1/2-1 = -1/2 and;

x = -1/2-1 = -3/2

x = -1/2 or -3/2

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Let y′′′−9y′′+20y′=0. find all values of r such that y=erx satisfies the differential equation. if there is more than one correc
DerKrebs [107]

we are given

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Firstly, we will find y' , y'' and y'''

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First derivative is

y'=re^{rx}

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Third derivative is

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now, we can plug these values into differential equation

and we get

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now, we can factor out

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