4t=r
a=pir^2
sub 4t for r
a=pi(4t)^2
a=pi16t^2
a(t)=16pi(t^2)
A. a(t)=16pi(t^2)
B. sub 4 for t
a(4)=16pi4^2
a(4)=16pi16
a(4)=16*16*3.14
a(4)=803.84 square units
A. a(t)=16pi(t^2)
B. 803.84 square units
Complete Question
A hypothetical population consists of eight individuals ages 13 14 17 20 21 22 24 30 years.
A: what is the probability that a person in this population is a teenager?
B: what is the probability of selecting a participant who is at least 20 years old?
We have that probability that a person in this population is a teenager and probability of selecting a participant who is at least 20 years old is
From the question we are told
A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.
a)
Generally the equation for the probability that a person in this population is a teenager is mathematically given as

P(T)=0.38
b)
Generally the equation for the probability of selecting a participant who is at least 20 years old is mathematically given as

P(T')=0.63
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You combine the like terms to get
2s^2y^2-4a^2sy+2a^4
For circumference it’s 12x3.14= 37.68
The answer would be -17.6.
Simplify 2.4 divided by 0.1 to 24 ( 6.4 - 24 )
Simplify ( -17.6 ).