Answer:
2.54 seconds
Step-by-step explanation:
We can use the following equation to model the vertical position of the ball:
S = So + Vo*t + a*t^2/2
Where S is the final position, So is the inicial position, Vo is the inicial speed, a is the acceleration and t is the time.
Then, using S = 2.5, So = 0.4, Vo = 14 and a = -9.8 m/s2, we have that:
2.5 = 0.4 + 14*t - 4.9t^2
4.9t^2 - 14t + 2.1 = 0
Solving this quadratic equation, we have that t1 = 2.6983 s and t2 = 0.1588 s.
Between these times, the ball will be higher than 2.5 m, so the amount of time the ball will be higher than 2.5 m is:
t1 - t2 = 2.6983 - 0.1588 = 2.54 seconds
400,000,000,000 + 90,000,000,000 + 6,000,000,000 + 600,000,000 + 60,000,000 + 300,000 + 40,000 + 2,000 + 800 + 10 + 1 Write the
Harman [31]
I think it's 4.96x10^11
if you input into a calculator and count the decimal from the end to the left it should give you your answer
p.s. that was a bad explanation, im sorry
Answer:
3
Step-by-step explanation:
sorry i cant answer it wont let me
Answer: idk
Step-by-step explanation:
