There are none
<h3>Further explanation</h3>
Given
a molecule of calcium sulfide
two valence electron of Calcium(Ca)
six valence electrons of Sulfur(S)
Required
number of lone pairs of electrons
Solution
Lewis structure shows the form of bonds that occur in the valence electrons of an element or compound
Valence electrons are electrons used in a chemical bond
To achieve stability, the element S needs 2 more electrons which are obtained from 2 electrons from the Ca element,
A lone pair electron means refers to an unshared pair of electrons(not bonding to the other atoms)
This condition usually occurs in covalent bonds
As we know, the bond between Ca, which is a group 2 (metal) with Sulfur in group 16, is an ionic bond because it occurs between metal and non-metal ions, so there is no sharing of electrons, but there is a release of electrons from Ca ions to S ions to form an octet. , so all the valence electrons in S are paired
= 0.05 mol C₂H₂