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gulaghasi [49]
3 years ago
8

A horse was 6,200 meters north of a barn. For 22.5 minutes, the horse ran toward the barn at 152 meters per minute. In that time

, how far did the horse run?
Chemistry
1 answer:
lutik1710 [3]3 years ago
6 0

3420‬m

Explanation:

Given parameters:

Length of path = 6200m

time taken for the horse to run = 22.5min

speed = 152meters/minute

Unknown:

Distance run by the horse = ?

Solution:

Speed is the rate of change of distance with time.

   Speed       =    \frac{distance}{time}

    Distance = speed x time

 

     Distance = 152 x 22.5 = 3420‬m

learn more:

Speed          brainly.com/question/5424148

#learnwithBrainly

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C

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6.07 grams is the theoretical yield of calcium phosphate (Ca₃(PO₄)₂).

<h3>How we calculate mass from moles?</h3>

Mass of any substance can be calculated by using moles as:

n = W/M, where

W = required mass

M= molar mass

Given chemical reaction is:

3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂

From the stoichiometry it is clear that:

3 moles of Ca(NO₃)₂ = produce 1 mole of Ca₃(PO₄)₂

Given mass of Ca(NO₃)₂ = 96.1g

Mole of Ca(NO₃)₂ = 96.1g/164g/mol = 0.5859moles

So, 0.5859 moles of Ca(NO₃)₂ = produce 0.5859×1/3 = 0.0196 moles of Ca₃(PO₄)₂

Required mass of Ca₃(PO₄)₂ will be calculated by using moles as:

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7 0
2 years ago
A solution that is a 4 on pH scale is a
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3 years ago
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A 45 mL sample of nitrogen gas is cooled from 135ºC to 15C in a container that can contract or expand at constant pressure. Wha
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Answer:

V₂ =31.8 mL

Explanation:

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Initial  volume of gas = 45 mL

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Final temperature = 15°C (15+273 =288 K)

Final volume of gas = ?

Solution:

The given problem will be solve through the Charles Law.

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Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

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T₂ = Final temperature

Now we will put the values in formula.

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8 0
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