Answer: All are correct except for "carries energy only through matter
Explanation: E2020
In question 13 answer B is the correct one since a catalyst is a chemical that can be added to a reaction to increase the reaction rate without being consumed in the process. In this way, a catalyst accelerates a reaction by decreasing the energy barrier necessary for the reaction to occur or by changing the reaction mechanism. The most common types of catalysts are enzymes, acid base catalysts and heterogeneous catalysts, mostly composed of solids in which the reactants adhere.
In the reaction you have in the question, they use an acid catalyst, H3O+. This catalyst changes the reaction mechanism of 2-butene in 1-butene without being consumed, since it appears at the beginning and at the end of the transformation of 2 butene into 1-butene. The reaction mechanism would be the following
In question 14 the correct answer is option B since the law of velocity of a reaction will be governed by the slow step of the mechanism through which it occurs. In the slow step the chemical species have a harder time transforming because they need more energy to do it, then they will do it in a slower way and the reaction will take longer to occur. Therefore, the slow step is the one that will determine the total speed of the reaction and the speed law must be in terms of that process. The speed of the other two steps is so fast that it is negligible.
Answer:
Chlorine is more electronegative than iodine. The electronegativity of chlorine is 3.16. The electronegativity of iodine is 2.66.
Answer:
No, have you ever listen that this compound has 1.5 electrons in outer most shell??? No, so oxidation state is always in integral number like, 1,2 3 etc
Explanation:
Order of reaction may be in fraction, but not oxidation state
Answer:
B
Explanation:
First of all it is important to know that a half filled orbital is particularly stable. In phosphorus all the electrons occur singly in the 3p sublevel minimizing inter electronic repulsion hence it is more difficult to remove an electron from this energetically stable arrangement. In sulphur, electrons are paired in one of the 3p orbitals thereby lowering the energy of that level due to instability caused by interelectronic repulsion between two electrons in the same orbital.
