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Kipish [7]
3 years ago
15

During a​ sale, a dress is marked down from a selling price of ​$ to a sale price of ​$. What is the percent​ markdown?

Mathematics
1 answer:
ElenaW [278]3 years ago
6 0

Complete question :

35%

Answer:

Step-by-step explanation:

Selling price = $68

Markdown price = $44.20

Percentage markdown :

Markdown / selling price * 100%

((68 - 44.20) / 68) * 100%

(23.8 / 68) * 100%

0.35 * 100%

= 35%

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PLEASE HELP QUESTION IN PICTURE
sp2606 [1]

Answer:

b = 55

d = 55

Step-by-step explanation:

Part B:

1. We can see that m∠C (25 degrees), the angle with 100 degrees, and ∠B are adjacent angles that add up to 180 degrees.

  • This means that b + 25 + 100 = 180

2. (Solving equation above)

Step 1: Simplify both sides of the equation.

  • b + (25+100)=180
  • b + 125 = 180

Step 2: Subtract 125 from both sides.

  • b + 125 - 125 = 180 - 125
  • b = 55

Therefore, b = 55.

Part D:

1. The exterior angle theorem states that the exterior angle of a triangle is congruent to the sum of the two opposing interior angles.

  • This means that 110 = d + 55

2. (Solving)

Step 1: Subtract 55 from both sides.

  • 110-55 = d + 55-55
  • 55 = d

Therefore, d = 55.

5 0
2 years ago
What is the point 2,1 dilated by the scale factor of 2.5
Inga [223]
The answer would be -0.4
6 0
3 years ago
Read 2 more answers
What is the percent increase rounded to the nearest percent ,from 5 to 8
krok68 [10]
The increase from 5 to 8 was by 60%.
5 0
3 years ago
5. – 3(1 + 6r) = 14 - 7​
MAVERICK [17]

Answer:

r= -1.8

Step-by-step explanation:

Distribute

-3-18r=14-7

Combine like terms

-3-18r=7

add 3 to both sides

-18r=10

divide by -18

r=-1.8

3 0
3 years ago
1.Assume that 20 squirrels are put in an enclosed wildlife ranch and the squirrel population grows for the next 5 years, as show
stiv31 [10]

Answer:

For the first group we have the pairs:

year           population

0                20

1                 80

2                320

3                 1,280

4                 5,120

5                 20,480

Here we can see that the population quadruples each year

(4*20 = 80, 80*4 = 320, 320*4 = 1,280, etc...)

then the population equation is:

P(0) = 20

P(1) = 20*4

P(2) = (20*4)*4 = 20*4^2

We already can see the pattern, then we can write this relationship as:

P(t) = A*(4)^(t)

Where:

t represents time in years, and A is the initial population, that we know it is 20, then:

P(t) = 20*(4)^t

This is the function that represents the table.

B) Now we have a group of 20 squirrels and the population triples each year, with the same reasoning than before we can write the equation that models this situation as:

Q(t) = 20*(3)^t

C) Now, if the initial population of the second group is 40, the equation becomes:

Q(t) = 40*(3)^t

The population by year 3 is given by replacing t by 3, then:

Q(3) = 40*(3)^3 = 1080

And the population of the other group in year 3 is seen in the table, it is 1,280, then the population of the first group is bigger by year 3, and it is greater by:

1,280 - 1,080 = 200

So the first group is larger by 200 squirrels.

3 0
3 years ago
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