For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
<h3>
Integers divisible by 3</h3>
The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.
<h3>Proof for the divisibility</h3>
111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)
222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)
213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)
27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)
Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.
Learn more about divisibility here: brainly.com/question/9462805
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Answer:
10f-30g
Step-by-step explanation:
we have:
5(2f - 6g)
we apply distributive property:
5(2f - 6g)
5*2f+5*(-6g)
finally we have:
10f-30g
Answer:
x = 41/3
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
7(1x - 3) = 4(x + 5)
<u>Step 2: Solve for </u><em><u>x</u></em>
- Simplify: 7(x - 3) = 4(x + 5)
- Distribute: 7x - 21 = 4x + 20
- Subtract 4x on both sides: 3x - 21 = 20
- Add 21 on both sides: 3x = 41
- Divide 3 on both sides: x = 41/3
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitute: 7(1(41/3) - 3) = 4(41/3 + 5)
- Multiply: 7(41/3 - 3) = 4(41/3 + 5)
- Subtract/Add: 7(32/3) = 4(56/3)
- Multiply: 224/3 = 224/3
Here, we see that 224/3 is indeed equivalent to 224/3. ∴ x = 41/3 is a solution to the equation.
And we have our final answer!
Slope is 1/2 and the y intercept is -1
Answer:
OR
x=\frac{3}{4} ±i\frac{\sqrt{39}}{4}\\
Step-by-step explanation:
