y - 3
g(y) = ------------------
y^2 - 3y + 9
To find the c. v., we must differentiate this function g(y) and set the derivative equal to zero:
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3)
g '(y) = --------------------------------------------
(y^2 - 3y + 9)^2
Note carefully: The denom. has no real roots, so division by zero is not going to be an issue here.
Simplifying the denominator of the derivative,
(y^2 - 3y + 9)(1) - (y - 3)(2y - 3) => y^2 - 3y + 9 - [2y^2 - 3y - 6y + 9], or
-y^2 + 6y
Setting this result = to 0 produces the equation y(-y + 6) = 0, so
y = 0 and y = 6. These are your critical values. You may or may not have max or min at one or the other.
Answer:
x=55°
Step-by-step explanation:
x=90-35
x=55°
(because its x+35=90°)
Answer:
900 cubic units
Step-by-step explanation:
V= base area *height of prism
Area of base is 1/2*15*8 =60
V=60*15
V=900
Answer:
The answer to your question is the letter B) y = 3x - 3
Step-by-step explanation:
Data
Point = (2, 3)
slope = m = 3
Process
To solve this problem just substitute the values given in the slope-point equation.
Formula
y - y1 = m(x - x1)
x1 = 2 y1 = 3
-Substitution
y - 3 = 3(x - 2)
-Expand
y - 3 = 3x - 6
-Solve for y
y = 3x - 6 + 3
-Result
y = 3x - 3
