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2 years ago

BEING TIMED !! In circle O, the length of arc AB is 2(pi) and the radius is 5. Find the

Mathematics

1 answer:

inn [45]2 years ago

8 0

Answer:

31.4

Step-by-step explanation:

3.14 x 2 x 5 = 31.4

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Lilit [14]

Answer:

1) 2m + 3m2 - 4m=7

7) 3m2 – 2m + 4m= 11

8) 20 + 109 + 39 - 4= 164

3) 2m + 4m - 3m2= -3

9) 4xy + x + 2xy= 0

4) 2y + 14x - 7x + 9y= 18

10) 6m2 - 6m - 9m2= -51

Step-by-step explanation:

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3 years ago

Find the product. 5.28 · 1.4 = _____ 7.392 2.64 73.92 7.362

stepan [7]

I would say that it is 7.392 :)

4 0

3 years ago

Read 2 more answers

Solve the equation please

Debora [2.8K]

Answer:

what equation I don't see one

6 0

2 years ago

5 8/25 as a decimal show work

bekas [8.4K]

Answer:

Split the number into the whole number component and fraction component.

5 8/25= 5+8/25.

For the denominator, recognize that

25×4=100.

Multiple =4.

Multiply the numerator and the denominator by the multiple 4.

8×4/ 25×4.

Simplify.

32/100=0.32

Combine the whole number component with the decimal.

5+0.32=5.32

<h3>I hope this helps</h3>

3 0

3 years ago

7. Are the ordered pairs below an arithmetic sequence or geometric

DochEvi [55]

Answer:

8. Arithmetic Progression

9. $f(9) = 300$

Step-by-step explanation:

Given

$\{(1,55)\ (2, 45)\ (3, 35)\ (4, 25)\}$

Solving (8): Arithmetic or Geometric

We start by checking if it is arithmetic by checking for common difference (d).

$d = y_2 - y_1 = y_3 - y_2 = y_4 - y_3$

This gives:

$d = 45 - 55 = 35 - 45 = 25 - 35$

$d = -10 = -10 = -10$

$d=-10$

Because the common difference is equal, then it is an arithmetic progression

Solving (8):

$f(n) = f(1) + f(n-1)$

To find f(9), we substitute 9 for n

$f(9) = f(1) + f(9-1)$

$f(9) = f(1) + f(8)$

We need to solve for f(8); substitute 8 for n

$f(8) = f(1) + f(8 - 1)$

$f(8) = f(1) + f(7)$

We need to solve for f(7); substitute 7 for n

$f(7) = f(1) + f(7 - 1)$

$f(7) = f(1) + f(6)$

We need to solve for f(6); substitute 6 for n

$f(6) = f(1) + f(6 - 1)$

$f(6) = f(1) + f(5)$

We need to solve for f(5); substitute 6 for n

$f(5) = f(1) + f(5 - 1)$

$f(5) = f(1) + f(4)$

From the function, f(4) = 25 and f(1) = 55.

So:

$f(5)=55 + 25$

$f(5)=80$

$f(6) = f(1) + f(5)$

$f(6) = 55 + 80$

$f(6) = 135$

$f(7) = f(1) + f(6)$

$f(7) = 55 + 135$

$f(7) = 190$

$f(8) = f(1) + f(7)$

$f(8) = 55 + 190$

$f(8) = 245$

$f(9) = f(1) + f(8)$

$f(9) = 55 + 245$

$f(9) = 300$

8 0

3 years ago