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netineya [11]
3 years ago
7

A woman put $580 into a savings account for one year. The rate of interest on the account was 6½%. How much was the interest for

the year in dollars and cents? (Round to the nearest cent)
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0

Answer:

Step-by-step explanation:

principal amount by women for savings = $ 580

duration = 1 year and rate of interest on it = 6 .1/2 % = 13/200

now amount of interest she'll be earning = $580 x 1 x 13 /200 = $37.7

thats  37 dollar 70 cents

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galben [10]

Answer:

-10x +4

Step-by-step explanation:

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3 years ago
How do you solve for the area for a complex figure
Dmitriy789 [7]

Step-by-step explanation:

It varies depending on the structure of the figure your taling about. If it is a bunch of squares or rectangles, you get the perimeter of all sides and then you try to make the figure into smaller squares or rectangles. After that now find the perimeter of the new side (opposit side should tell you) and then find the area for all the rectangles and squares. After that step, you add all the areas together and...viola!!!! You get the area of the complex figure. If it is not a rectangle please comment with the object and I could help you.

5 0
3 years ago
A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the
leva [86]

The length of the bridge is the distance from the beginning to the end.

<em>The distance b between each beam is 9ft.</em>

Let:

<em />I \to<em> I-Beam</em>

<em />d_I \to<em> distance between I beam and the bridge</em>

<em />b \to<em> distance between each I beam</em>

<em />

Given that:

I = \frac 34 ft\\

d_I = 3 ft

<em />Length = 55ft\ 6in<em> --- length of the  bridge</em>

<em />

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

L_1 = 6 \times I

L_1 = 6 \times \frac 34

L_1 = \frac {18}4

L_1 = 4.5ft

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

d_1 =2 \times d_I

d_1 =2 \times 3ft

d_1 =6ft

There are 5 spaces between the I-beams

So, the length of the total spaces is:

L_2 = 5 \times b

L_2 = 5b

The total length is:

Length = L_1 + d_1 + L_2

So, we have:

4.5ft + 6ft + 5b = 55ft\ 6in

Collect like terms

5b = 55ft\ 6in - 4.5ft - 6ft

5b = 44.5ft\ 6in

Convert inches to feet

5b = 44.5ft\ + \frac{6}{12}ft

5b = 44.5ft\ + 0.5ft

5b = 45ft

Divide both sides by 5

b = 9ft

<em>Hence, the distance (b) between each beam is 9ft.</em>

Read more about lengths at:

brainly.com/question/22059747

3 0
3 years ago
If two angles are supplementary , they must
-BARSIC- [3]
If the two angles are supplementary, they must equal 180 degrees

7 0
4 years ago
Read 2 more answers
The function f(t) = 33 sin (pi over 2t) − 20 models the temperature of a periodic chemical reaction where t represents time in h
Gennadij [26K]
The given function is
f(t) = 33 sin( \frac{ \pi }{2} t) - 20
with
t = time, hours
f = temperature, °C


Because the maximum and minimum values for the Sine function are +1 and -1 respectively,
The maximum value of f  = 33 - 20 = 13.
The minimum value of f = -33 - 20 = -53. 

The period, T,  is given by
\frac{2 \pi }{T} = \frac{ \pi }{2} \\ \\ T=4

Answer:
Maximum: 13°;  Minimum: -53°;  period: 4 hours
4 0
3 years ago
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