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BabaBlast [244]
3 years ago
10

What’s the answer??????

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
4 0

Answer:

50p

Step-by-step explanation:

you can add them all up together. 27+3+6+14=50!

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What is the square root of 8
sattari [20]

Answer:

Approximately 2.83

Step-by-step explanation:

4 0
3 years ago
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Expand (x-3)(x-8) to form a quadratic expression
AlladinOne [14]

Answer:

x^2 - 11x + 24

Step-by-step explanation:

Foil the equation

x^2 - 3x - 8x + 24

x^2 - 11x + 24

8 0
3 years ago
1st. (2 root 2 + root 3 ) ( 2 root 3 - root 2)
satela [25.4K]

Answer:

1st: 3*root6 + 5

2nd: 35*root2 + 115

3rd: 24*root2 - 20*root6 + 15*root3 - 18

4th: 17*root6 - 38

5th: 13*root10 - 42

Step-by-step explanation:

To simplify these expressions we need to use the distributive property:

(a + b) * (c + d) = ac + ad + bc + bd

So simplifying each expression, we have:

1st.

(2 root 2 + root 3 ) ( 2 root 3 - root 2)

= 4*root6 - 2*2 + 2*3 - root6

= 3*root6 - 4 + 9

= 3*root6 + 5

2nd.

(root 5 + 2 root 10) (3 root 5 + root 10)

= 3 * 5 + root50 + 6*root50 + 2*10

= 15 + 5*root2 + 30*root2 + 100

= 35*root2 + 115

3rd.

(4 root 6 - 3 root 3) (2 root 3 - 5)

= 8*root18 - 20*root6 - 6*3 + 15root3

= 24*root2 - 20*root6 + 15*root3 - 18

4rd.

(6 root 3 - 5 root 2 ) (2 root 2 - root 3)

= 12*root6 - 6*3 - 10*2 + 5*root6

= 17*root6 - 18 - 20

= 17*root6 - 38

5th.

(root 10 - 3 ) ( 4 - 3 root 10)

= 4*root10 - 3*10 - 12 + 9*root10

= 13*root10 - 30 - 12

= 13*root10 - 42

8 0
3 years ago
What is the formula of simple interest?​
Annette [7]

Answer:

simple interest = principle*rate*time

5 0
4 years ago
Read 2 more answers
Which students line segments have a midpoint of (-1,4)? Select all that apply A. Student 1 B. Student 2 C. Student 3 D. Student
SashulF [63]

Answer:

C. Student 3

E. Student 5

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

<u><em>Verify the midpoint of each student</em></u>

student 1

we have the endpoints

(-9,0) and (11,-8)

substitute in the formula

M(\frac{-9+11}{2},\frac{0-8}{2})

M(1,-4)

so

The midpoint is not (-1,4)

student 2

we have the endpoints

(-6,-1) and (4,-7)

substitute in the formula

M(\frac{-6+4}{2},\frac{-1-7}{2})

M(-1,-4)

so

The midpoint is not (-1,4)

student 3

we have the endpoints

(-5,2) and (3,6)

substitute in the formula

M(\frac{-5+3}{2},\frac{2+6}{2})

M(-1,4)

so

<u>The midpoint is equal to (-1,4)</u>

student 4

we have the endpoints

(-3,10) and (5,-2)

substitute in the formula

M(\frac{-3+5}{2},\frac{10-2}{2})

M(1,4)

so

The midpoint is not (-1,4)

student 5

we have the endpoints

(0,-3) and (-2,11)

substitute in the formula

M(\frac{0-2}{2},\frac{-3+11}{2})

M(-1,4)

so

<u>The midpoint is equal to (-1,4)</u>

therefore

Student 3 and student 5

3 0
4 years ago
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