Answer:
Options A, B and C are CORRECT PROPORTIONS
Step-by-step explanation:
Option A
3:5 = 6:10
The LHS must equal the RHS
3:5 is in it's lowest term.
6/10 will be in it's lowest term by dividing the numerator and denominator by 2.
6/10 = 3/5
Option B
3/6 and 5/10.
Diving 3/6 fractions by 3
= 1/2
Dividing 5/10 fraction by 5
= 1/2
Option C
Dividing 6/3 by 3 = 2
Dividing 10/5 by 5 = 2
Thats how you work through equivalent proportional fractions
Answer:
1275510204.08
Step-by-step explanation:
please first take square and then division
Hi there,
To find your answer you would, divide 2 by 10. That would give you 0.2. That means that every glass will have 0.2quarts of juice.
Hope this helped!
Ohhhh nasty ! What a delightful little problem !
The first card can be any one of the 52 in the deck. For each one ...
The second card can be any one of the 39 in the other 3 suits. For each one ...
The third card can be any one of the 26 in the other 2 suits. For each one ...
The fourth card can be any one of the 13 in the last suit.
Total possible ways to draw them = (52 x 39 x 26 x 13) = 685,464 ways.
But wait ! That's not the answer yet.
Once you have the 4 cards in your hand, you can arrange them
in (4 x 3 x 2 x 1) = 24 different arrangements. That tells you that
the same hand could have been drawn in 24 different ways. So
the number of different 4-card hands is only ...
(685,464) / (24) = <em>28,561 hands</em>.
I love it !
If you get 0 as the last value in the bottom row, then the binomial is a factor of the dividend.
Let's say the binomial is of the form (x-k) and it multiplies with some other polynomial q(x) to get p(x), so,
p(x) = (x-k)*q(x)
If you plug in x = k, then,
p(k) = (k-k)*q(k)
p(k) = 0
The input x = k leads to the output y = 0. Therefore, if (x-k) is a factor of p(x), then x = k is a root of p(x).
It turns out that the last value in the bottom row of a synthetic division table is the remainder after long division. By the remainder theorem, p(k) = r where r is the remainder after dividing p(x) by (x-k). If r = 0, then (x-k) is a factor, p(k) = 0, and x = k is a root.