Answer:
The final temperature is 85.86°C.
Explanation:
Given that,
Mass of tea = 200 g
Mass of glass = 150 g
Initial temperature = 25°C
We need to calculate the final temperature
When equilibrium is reached, assuming no heat flows to the surroundings
So,
We know that,
Specific heat of tea = 1.00 cal/gm° C
Specific heat of tea = 0.20 cal/gm° C
Put the value into the formula
Put the value of initial temperature
Hence, The final temperature is 85.86°C.
Answer:
The answer is = 5.81*10-7 N/m
Explanation:
From the above question, the first step to take is to find the magnitude of the net force per unit length acting on wire 3 due to the currents in the other wires
Solution
Given
The magnitude of the net force per unit length moving on wire 3 due to the currents in the other wires is
= I₃* B
= I₃*[-μ₀I₁/(2π*2d) + μ₋₀I₂/(2πd) + μ₀I₄/(2πd) + μ₀I₅/(2π*2d)] (+y direction)
Thus,
= μ₀I₃/(2πd) * (-I₁/2 + I₁ + I₄ + I₅/2)
Therefore, the magnitude of the net force per unit length acting on wire 3 due to the currents in the other wires is = 5.81*10-7 N/m
Answer:
-4.8 m/s²
Explanation:
Apply Newton's second law:
∑F = ma
F − mg = ma
300 N − (60 kg) (9.8 m/s) = (60 kg) a
a = -4.8 m/s²
The acceleration five seconds after jumping is 4.8 m/s² downward.
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