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Basile [38]
3 years ago
7

In the past, how did people use the systematic movement of celestial bodies? Select all that apply.

Physics
2 answers:
luda_lava [24]3 years ago
7 0

In past, people used the systematic movement of celestial bodies for making agricultural decisions, shipping navigation and for spiritual and religious practices.

Answer: Options 1, 2, and 4

<u>Explanation: </u>

The observation of systematic movement of celestial bodies comes under the field of Astrometry. The celestial mechanics which defines are the movement of celestial bodies is also a kind of Astrometry.

The celestial mechanics is used by the people in past to help in navigation during ship journey. Even the astrometry will help in predicting the seasons to be coming which will help in making agricultural decisions.

In astrology, the position of celestial bodies help in deciding the time for spiritual and religious practices. So, in ancient days, people used the systematic movement of celestial bodies in naked eyes to decide these.

vredina [299]3 years ago
5 0
The answer is actually a,b, and d
Brainliest?
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2 years ago
An engine absorbs 1.69 kJ from a hot reservoir at 277°C and expels 1.25 kJ to a cold reservoir at 27°C in each cycle.
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3 years ago
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3 years ago
you stretch a spring by a distance of 0.3 m. the spring has a spring constant of 440 n/m. when you release the spring, it snaps
Alina [70]

Answer:

19.8 J

Explanation:

According to the law of conservation of energy, the total mechanical energy of the spring (sum of kinetic energy and elastic potential energy) must be conserved:

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where we have

K_i is the initial kinetic energy of the spring, which is zero because the spring starts from rest (2)

U_i is the elastic potential energy of the spring when it is fully stretched

K_f is the kinetic energy of the spring when it reaches the natural length

U_f is the elastic potential energy of the spring when it reaches its natural length, which is zero because the stretch in this case is zero (3)

So

U_i = \frac{1}{2}k(\Delta x_i)^2

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U_i = \frac{1}{2}(440)(0.3)^2=19.8 J

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K_f= U_i = 19.8 J

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