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REY [17]
3 years ago
15

A scalloped hammerhead shark swims at a steady speed of 1.5 m/s with its 88 cm -cm-wide head perpendicular to the earth's 56 μT

magnetic field. What is the magnitude of the emf induced between the two sides of the shark's head? Express your answer using two significant figures.
Physics
1 answer:
Nadya [2.5K]3 years ago
8 0

Answer:

7.4 x 10⁻⁵ T.

Explanation:

Emf induced = BLv

Where B is magnetic field , L is length of rod or any other object moving in magnetic field and v is velocity of moving rod.

Here B = 56 x 10⁻⁶ T

L = 88 X 10⁻² m

v = 1.5 m/s

emf induced = 56 x 10⁻⁶ x 88 x 10⁻² x 1.5

= 7.4 x 10⁻⁵ T.

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A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
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Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

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The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

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The ovaries in females and the testes in males are part of the
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Hope this helps :)

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