Answer:
Answer is in the picture. hope it helps.
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2 answers:
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The "explanation" for the problem has a typo in it. There are 11 possible ice cream/yogurt flavors to choose from, regardless of whether any are low-fat, so the total number of ways of choosing any 2 from the selection is
In particular we want to count the number of ways of picking 1 ice cream and 1 yogurt flavor from the low-fat variety. There are 6 total choices that are not low-fat of which we choose 0, 3 choices of low-fat ice cream of which we choose 1, and 2 choices of low-fat yogurt of which we also choose 1. In terms of the binomial coefficient, this is
So the probability of getting such a combination is
.
In particular we want to count the number of ways of picking 1 ice cream and 1 yogurt flavor from the low-fat variety. There are 6 total choices that are not low-fat of which we choose 0, 3 choices of low-fat ice cream of which we choose 1, and 2 choices of low-fat yogurt of which we also choose 1. In terms of the binomial coefficient, this is
So the probability of getting such a combination is
Answer:
95.44%
Step-by-step explanation:
Mean rate (μ) = 160 euros
Standard deviation (σ) = 8 euros
For any given rate, X, the z-score is:
For X = 144 euros:
For X= 176 euros
In a standard distribution, a z-score of -2 corresponds to the 2.28th percentile, while a z-score of 2 corresponds to the 97.72th percentile.
Therefore, the percentage of hotels with rates between 144 and 176 euros is: