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3 years ago

6

Point Q ′ Q ′ Q, prime is the image of Q ( 3 , − 4 ) Q(3,−4)Q, left parenthesis, 3, comma, minus, 4, right parenthesis under a r

eflection across the x xx-axis.

1 answer:

OLEGan [10]3 years ago

8 0

Answer:

Q'(3, 4 )

Step-by-step explanation:

Under a reflection in the x- axis

a point (x, y ) → (x, - y ), thus

Q(3, - 4 ) → Q'(3, 4 )

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Find the area of a trapezium whose parallel sides are 25 cm ,13 cm and other sides are 15 cm and 15 cm

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2 years ago

Read 2 more answers

The race begins at the rate of 1.5 meters per second. what distance, d, is covered after t second

Nitella [24]

1 second = 1.5 meters
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4 0

3 years ago

Consider the following pair of points.

dedylja [7]

Answer:

The answer is

<h2> $\sqrt{265} \: \: or \: \: 16.28 \: \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

<h3> $d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$ </h3>

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(9,-8) and (-7,-5)

The distance between them is

$d = \sqrt{ ({9 + 7})^{2} + ({ - 8 + 5})^{2} } \\ = \sqrt{ {16}^{2} + ( { - 3})^{2} } \\ = \sqrt{256 + 9} \: \: \: \: \: \: \: \: \: \\ = \sqrt{265} \: \: \: \: \: \: \\ = 16.27882$

We have the final answer as

$\sqrt{265} \: \: or \: \: 16.28 \: \: \: \: units$

Hope this helps you

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3 years ago