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Zepler [3.9K]
3 years ago
5

Will mark brainiest btw if I fail this I fail math pls no guessing

Mathematics
1 answer:
lesya [120]3 years ago
7 0

Answer:

72 is the least common multiple

Step-by-step explanation:

The first one is the multiples of 9 and the second one is of 8

The only one they have in common is the number 72

You might be interested in
An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining.
strojnjashka [21]

Answer:

1. The 90% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2 is (-2411.84, -1332.16).

2. The point estimate for the true difference between the population means is of -1872.

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of Normal Variables:

When two normal variables are subtracted, the mean is the subtraction of the means while the standard deviation is the square root of the sum of the variances.

A sample of 212 brakes using Compound 1 yields an average brake life of 47,895 miles. The population standard deviation for Compound 1 is 1590 miles.

This means that \mu_1 = 47895, \sigma_1 = 1590, n = 212, s_1 = \frac{1590}{\sqrt{212}} = 109.2

A sample of 180 brakes using Compound 2 yields an average brake life of 49,767 miles. The population standard deviation for Compound 2 is 4152 miles.

This means that \mu_2 = 49767, \sigma_2 = 4152, n = 180, s_2 = \frac{4152}{\sqrt{180}} = 309.47

True difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2.

This is the distribution 1 - 2. So

\mu = \mu_1 - \mu_2 = 47895 - 49767 = -1872

This is also the point estimate for the true difference between the population means, which is question 2.

s = \sqrt{s_1^2+s_2^2} = \sqrt{109.2^2+309.47^2} = 328.17

90% confidence interval

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = zs = 1.645*328.17 = 539.84

The lower end of the interval is the sample mean subtracted by M. So it is -1872 - 539.84 = -2411.84

The upper end of the interval is the sample mean added to M. So it is -1872 + 539.84 = -1332.16.

The 90% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2 is (-2411.84, -1332.16).

5 0
4 years ago
Harry drove 2 hours on the freeway then decreased his speed by 20mph and drove 6 more hours. total trip was 352 what was his spe
poizon [28]
Recall your d = rt, distance = rate * time

we know the total trip was 352miles, so, let's say he was going for the first 2hrs at "r" speed, he went "d" miles, then he slowed down to "r - 20" and went 6 more hours, since the total trip is 352 miles, the 6hrs take the slack from 352 - d, and that's how many miles he covered on those 6hours

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{before slowing}&d&r&2\\
\textit{after slowing}&352-d&r-20&6
\end{array}
\\\\\\

\begin{cases}
\boxed{d}=2r\\
352-d=(r-20)6\\
----------\\
352-\boxed{2r}=(r-20)6
\end{cases}

solve for "r".
7 0
4 years ago
Interest = $72.30<br> Principle = ?<br> Rate = 5%<br> Time = 3 years
gladu [14]

Answer:

Step-by-step explanation:

Answer:

P = $ 482.00

Equation:

P = I / rt

Calculation:

First, converting R percent to r a decimal

r = R/100 = 5%/100 = 0.05 per year,

then, solving our equation

P = 72.3 / ( 0.05 × 3 ) = 482

P = $ 482.00

The principal required to

accumulate interest of $ 72.30

on a rate of 5% per year for 3 years is $ 482.00.

hope it helps :)

7 0
3 years ago
Jennifer paddles her canoe 3/5 in 1/5 hours. How long would it take her to go 8 miles?
Rudik [331]

Asumming that 3/5 is the number of miles Jennifer has gone in 1/5 of an hour. We can take 60 (# of minutes in an hour) divided by 5, which equals 12. So 3/5 is 36 minutes. to figure out how many 1/5 are in 8 miles we would take 8 times 5 which is 40. We would then take 3 times 8, which is 24. 40 - 24 = 16. So 16 times 5 = 80 minutes. 80 divided by 60 (# of minutes in an hour) is 1 hour and 20 minutes. So it takes Jennifer 1 hour and 20 minutes to travel 8 miles.

4 0
3 years ago
What is the equation in point slope form of the line that passes the points (2,-3) and(-5,8)
Grace [21]

Answer:

y+3=-11/7(x-2)

Step-by-step explanation:

y-y1=m(x-x1)

m=(y2-y1)/(x2-x1)

m=(8-(-3))/(-5-2)

m=(8+3)/(-7)

m=11/-7

m=-11/7

y-(-3)=-11/7(x-2)

y+3=-11/7(x-2)

4 0
3 years ago
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