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Kay [80]
2 years ago
15

A fenced-in rectangular area has a perimeter of 40 ft. The fence has a post every 5 ft.

Mathematics
1 answer:
sertanlavr [38]2 years ago
7 0
8 post 4ft is the length 2ft ,yes if you dived 5 from 40 that is how many post , then you dived how many posts and that is the  height then you dvide that and that is your width.

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Need help answering this question
Nikolay [14]

Answer:

incorrect.

Step-by-step explanation:

Why?

72 times 2 is 144. You have a remainder of 4 left. Therefore the answer being 2r4

6 0
3 years ago
What is the value of x in the inequality start fraction seven minus two x over negative four end fraction plus two less than neg
algol13

Answer:

x

Step-by-step explanation:

\frac{7-2x}{-4} +2

Subtract 2 from both sides

\frac{7-2x}{-4}

mutliply both sides by -4, flip the inequality

7-2x >4x+8

Add 2x on both sideds

7>6x+8

Subtract 8 from both sides

-1>6x

Divide both sides by 6

x

3 0
3 years ago
Theres 2 here, pleaseeee help
True [87]
With the first one, you just plug the numbers inside the parentheses into f(x). Therefore:
f(-2)=40
f(-1)=18
f(0)=8
f(1)=10
f(2)=24

For the second one, you look at the table and find where x=1. The number there is 24, so therefore, f(1)=24
4 0
3 years ago
Enzymes : Fish that has been dried in the song keeps longer than wet fish. ​
Nonamiya [84]

Answer:

If the question is fix the sentence than here:

Step-by-step explanation:

A fish that has been dried in the sun lasts longer than a wet fish.

3 0
2 years ago
Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
3 years ago
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