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e-lub [12.9K]
3 years ago
10

Help me asap I don’t know what to do

Mathematics
1 answer:
sattari [20]3 years ago
3 0

Answer:

J 8.5 >=2.5p

Step-by-step explanation:

To do this plug in 3.4 for each version of p. The only one that would be true would be J.

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3. 03 MC
timama [110]

Answer: a lower credit score

Step-by-step explanation:

8 0
2 years ago
Which describes changing an angle of rotation?
givi [52]
I think the answer is B). because if the angle is changed if it turned on a fixed point. its changed if it translated or if the rays are changed, neither is it changed if it translated to the right either.
3 0
3 years ago
Read 2 more answers
If the equation 3x-5y=-3, what is the value of y when x is 1
pantera1 [17]
The answer is: 6/5

Here is why:
3x - 5y = -3
3(1) - 5y = -3
3 - 5y = -3
3 - 5(6/5) = -3
-3 = -3

6 0
3 years ago
Explanation plsss..​
ollegr [7]

Answer:

You will need 20 sides to complete the loop.

Step-by-step explanation:

The question isn't quite clear given how small the corner is, but I assume that we are looking to complete the circle if the pentagon and square are repeated in a loop

We can also see - assuming that those are proper equal-sided polygons, that PQ is the same length as PV

With that in mind, We can solve this by noting that the angle of a corner in a square is 90 degrees, and in a pentagon it's 108 degrees.

108 - 90 is equal to 18. This means that PQ is at eighteen degrees to YP. Also, QM, (which will be equivalent to the next VP is eighteen degrees to PQ.

This means that each polygon is rotated 18 degrees relative to it's neighbour.

With all that we can say that the total polygons we need to form a circle is 360/18 = 20, So you will need 20 polygons, or ten squares and ten pentagons to complete the loop.

4 0
3 years ago
A sinusoidal carrier wave has an amplitude of 5 volts, a frequency of 1MHz, and zero phase angle. Select the correct carrier wav
Vedmedyk [2.9K]

Answer:

The correct answer is b.

Step-by-step explanation:

The wave equation is given generally as:

c(x, t) = Acos(kx - wt)

Where A = amplitude

k = wave number

w = angular frequency.

x = horizontal distance moves by the wave.

t = time

The options show to us that the wave depends only on t and not (x, t).

Hence, the wave equation becomes:

c(t) = Acos(wt)

Given that:

A = 5 V

f = 1 * 10⁶ Hz

Angular Frequency, w, is given as:

w = 2πf

w = 2 * π * 1 * 10⁶ Hz

w = 2π(1 * 10⁶)

The wave equation becomes:

c(t) = 5cos(2*π*1*10⁶)

The correct answer is b.

6 0
3 years ago
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