In this question, we want to compare several numbers with different denominators and find out which number is the least. To compare this number, we have to change the denominator into the same number by finding the least common multiple (LCM) of the 4 numbers. The factor of each number will be:
3= 3 ^1
5= 5^1
8= 2 * 2 * 2 = 2^3
2= 2^1
We can find the LCM by multiplying a higher exponent of each prime number. The LCM will be:3^1 * 5^1 * 2^3 = 120
Each number will be:
Tiger= 2/3 * 40/40= 80/120
Redbird = 4/5 * 24/24= 96/120
Bulldogs = 3/8 * 15/15 = 45/120
Titans = 1/2 * 60/60 = 60/120
As you can see, the team with the lowest chance to play is Bulldogs = 45/120
C.(x-2)^2+(y+10)^2=9, plug the numbers in the original formula.
P = 4x + 2y
additional info.
<span>x+2y <u><</u> 10
y <u><</u> 2
x <u>></u> 0
y <u>></u> 0
y can only be 0, 1, and 2.
x + 2(0) <u><</u> 10 = x <u><</u> 10
x + 2(1) <u><</u> 10 = x + 3 <u><</u> 10 = x <u><</u> 10 - 3 = x <u><</u> 7
x + 2(2) <u><</u> 10 = x + 4 <u><</u> 10 = x < 10 - 4 = x <u><</u> 6
x = 10 ; y = 0 : P = 4(10) + 2(0) = 40 + 0 = 40
x = 7 ; y = 1 : P = 4(7) + 2(1) = 28 + 2 = 30
x = 6 ; y = 2 : P = 4(6) + 2(2) = 24 + 4 = 28
The maximum value of P is 40. Where x is 10 and y is 0.</span>
The first step in solving quadratic equations by finding square roots is; C:square root both sides to isolate x
<h3>How to solve quadratic equations?</h3>
To answer this question, we will take an example of a quadratic equation that we need to find the square root as;
x² = 36
Now, to get the roots which are the values of x, we will first have to take the square root of both sides to Isolate x. Thus;
√x² = √36
x = ±6
Read more about quadratic equations at; brainly.com/question/1214333
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Answer:
The minimum cost is $9,105
Step-by-step explanation:
<em>To find the minimum cost differentiate the equation of the cost and equate the answer by 0 to find the value of x which gives the minimum cost, then substitute the value of x in the equation of the cost to find it</em>
∵ C(x) = 0.5x² - 130x + 17,555
- Differentiate it with respect to x
∴ C'(x) = (0.5)(2)x - 130(1) + 0
∴ C'(x) = x - 130
Equate C' by 0 to find x
∵ x - 130 = 0
- Add 130 to both sides
∴ x = 130
∴ The minimum cost is at x = 130
Substitute the value of x in C(x) to find the minimum unit cost
∵ C(130) = 0.5(130)² - 130(130) + 17,555
∴ C(130) = 9,105
∵ C(130) is the minimum cost
∴ The minimum cost is $9,105