We need to figure out how much string would be left, after taking away the first two pieces.
We know that the first piece is 20 inches long, so we can say that there is 52-20 inches left, or 32 inches.
The second piece is between 12 and 18 inches, meaning that there would be between 32-12 and 32-18 inches left for the third piece, or 20 and 14 inches. This means that the third piece would be at least 14 inches long, but no more than 20, since we don’t have more string than that (20+12+20=52, and 20+14+18=52)
So we can say that x is greater or equal to 14, but less than or equal to 20, or:
14<=x<=20 (“<=“ is written like a normal “<“ sign with a line _ right under it)
Answer:
120 leaves
Step-by-step explanation:
If the caterpillar eats 75 leaves in 5 hours and continues to eat at the same rate, the number of leaves eaten is simple, 120 leaves.
How I found the answer:
First, I divided 75 by 5 and got 15, then I multiplied 8 to 15 and got 120.
We have y - 2 = m(x + 5), where m = (-1 - 2)/(10 + 5) = -3/15 = -1/5;
Then y - 2 = (-1/5)(x + 5);
5y - 10 = (-1)(x + 5);
5y - 10 = -x - 5;
x + 5y - 5 = 0 is the equation of the line.
L x w = 150+175t
=> l = (150+175t)/25
l = [25(6+7t)/25]
l = 6+7t
The expression of the length is l=6+7t
Step-by-step explanation:
the diameter of a circle is simply 2×radius.
2×15.4 = 30.8 m
the diameter is 30.8 m is true.
the circumference of a circle is
2×pi×radius
2×pi×15.4 = 30.8×pi m
the circumference is 30.8pi m is true.
therefore, the circumference can be found using
2(pi)(15.4)
is true.
now, doing the pi multiplication :
30.8 × pi = 96.76105373... m
the approximate circumference is 96.7 m is true.
6 diameters would be
30.8×6 = 184.8 m
that is much longer than the circumference.
so, more than 6 diameters could be wrapped around the circle is false, if we understand it that this is supposed to wrap the circle once without any overhanging remainder.
