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3 years ago

6

This one is mildish please hepl

1 answer:

seraphim [82]3 years ago

3 0

-18 -9 0 9 18 this good?

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In a club there is 13 women and 8 men. A committee of 9 women and 4 men is to be chosen. How many different ways are there to se

sammy [17]

Answer:

The total number of ways to select 9 women and 4 men for the committee is 50,050.

Step-by-step explanation:

The club has 13 female members and 8 male members.

The committee to be formed must have 9 female members and 4 male members.

The possible number of ways to select 9 female from 13 females is:

$n(F)={13\choose 9}=\frac{13!}{9!(13-9)!}=715$

The possible number of ways to select 4 male from 8 males is:

$n(M)={8\choose 4}=\frac{8!}{4!(8-4)!}=70$

Compute the possible total number of ways to select 9 women and 4 men for the committee as follows:

Total number of ways to select 9 women and 4 men = n (F) × n (M)

$=715\times70\\=50050$

Thus, the total number of ways to select 9 women and 4 men for the committee is 50,050.

3 0

3 years ago

A breeder reactor converts uranium-238 into an isotope of plutonium-239 at a rate proportional to the amount of uranium-238 pres

topjm [15]

Let $U(t)$ denote the amount of uranium-238 in the reactor at time $t$ . As conversion to plutonium-239 occurs, the amount of uranium will decrease, so the conversion rate is negative. Because the rate is proportional to the current amount of uranium, we have

$\dfrac{\mathrm dU}{\mathrm dt}=-kU$

where $k>0$ is constant. Separating variables and integrating both sides gives

$\dfrac{\mathrm dU}U=-k\,\mathrm dt\implies\ln|U|=-kt+C\implies U=Ce^{-kt}$

Suppose we start some amount $u$ . This means that at time $t=0$ we have $U(0)=u$ , so that

$u=Ce^{-0k}\implies C=u\implies U=ue^{-kt}$

We're given that after 10 years, 99.97% of the original amount of uranium remains. This means (if $t$ is taken to be in years) for some starting amount $u$ ,

$0.9997u=ue^{-10k}\implies k=-\dfrac{\ln(0.9997)}{10}$

The half-life is the time $t_{1/2}$ it takes for the starting amount $u$ to decay to half, $0.5u$ :

$0.5u=ue^{-kt_{1/2}}\implies t_{1/2}=-\dfrac{\ln(0.5)}k=\dfrac{10\ln2}{\ln(0.9997)}$

or about 23,101 years. Notice that it doesn't matter what the actual starting amount is, the half-life is independent of that.

7 0

3 years ago

- + 106 = 315 cubic inches

WARRIOR [948]

Answer:585 cubic inch

Step-by-step explanation:

volume=15 x 10 x 3 + 9 x 3 x 5

Volume=450 + 135

Volume=585

8 0

4 years ago

Convert to standard form 2.9x10 to the power of 3 plssss help

quester [9]

Answer:

To write a linear expression in standard form, rearrange the terms in alphabetical order.

$2.9$ × $10^3$

But, if you need to write it in scientific notation, the answer is 2,900.

5 0

3 years ago

Plz, Help me with this question.

amid [387]

Answer:

12x + 16y

Step-by-step explanation:

Multiply 4 and 3x to get 12x.

Multiply 4 and 4y to get 16y.

The sign stays positive because 4 is positive, so we end up with 12x + 16y.

5 0

3 years ago