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wolverine [178]
3 years ago
13

A 0.37 kg object is attached to a spring with a spring constant 175 N/m so that the object is allowed to move on a horizontal fr

ictionless surface. The object is released from rest when the spring is compressed 0.19 m. Find the force on the object when it is released. Answer in units of N. What is the acceleration at this instant? Answer in units of m/s^2.​
Physics
1 answer:
drek231 [11]3 years ago
3 0

Answer:

F=33.25\ N

a=89.8649\ m.s^{-2}

Explanation:

Given:

  • mass of the object, m=0.37\ kg
  • spring constant, k =175\ N.m^{-1}
  • compression in the spring, \Delta x=0.19\ m

<u>Now the force on the spring on releasing the compression:</u>

F=k. \Delta x

F=175\times 0.19

F=33.25\ N

<u>Now the acceleration due to this force:</u>

a=\frac{F}{m}

a=\frac{33.25}{0.37}

a=89.8649\ m.s^{-2}

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Dominik [7]

Answer:

The time taken for the race is 17.20 s.

Explanation:

It is given in the problem that a 62.0 kg sprinter starts a race with an acceleration of 1.44 meter per second square.The initial speed of the sprinter is zero as it starts from the rest.

Calculate the final speed of the sprinter.

The expression for the equation of the motion is as follows;

v^{2}-u^{2}= 2as

Here, u is the initial speed, v is the final speed, a is the acceleration and s is the distance.

Put u= 0, s=30 m and a= 1.44 ms^{-2}.

v^{2}-(0)^{2}= 2(1.44)(30)

v= 9.3 m^{-1}

Calculate time taken to cover 30 m distance.

The expression for the equation of motion is as follows;

s=ut+\frac{(1)}{2}at^2

Put u= 0, s=30 m and a= 1.44 ms^{-2}.

30=(0)t+\frac{(1)}{2}(1.44)t^2

t=6.45 s

Calculate the time taken to complete his race.

T= t+t'

Here, t is the time taken to cover 30 m distance and t' is the time taken to cover 100 m distance.

T=6.45+\frac{s'}{v}

Put s= 30 m, v= 9.3 m^{-1} and s'= 100 m.

T=6.45+\frac{(100)}{9.3}

T= 17.20 s

Therefore, the time taken for the race is 17.20 s.

6 0
4 years ago
3.2 Define conservation of energy.<br>​
Free_Kalibri [48]

Answer:

A principle stating that energy cannot be created or destroyed, but can be altered from one form to another.

Explanation:

5 0
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soaring birds and glider pilots can remain aloft for hours without expending power. Discuss why this is so.
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Since their wings and body develop the drag. When there is warm air then they expand their wings. Since,soaring birds and glider pilots have no engine, they always maintain their high speed to lift their weight in air for hours without expending power by convection

Explanation:

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The diagram below shows waves A and B in the same medium
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Answer:

2) twice the amplitude and half the wavelength

Explanation:

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6.If a 250. gram cart moving to the right with a velocity of .31 m/s collides inelastically with a 500. gram cart traveling to t
spin [16.1K]

Answer:

The total momentum of the system before the collision is 0.0325 kg-m/s due east direction.    

Explanation:

Given that,

Mass of the cart, m = 250 g = 0.25 kg

Initial velocity of the cart, u = 0.31 m/s (due right)

Mass of another cart, m' = 500 g = 0.5 kg

Initial velocity of the another cart u' = -0.22 m/s (due left)

Let p is the total momentum of the system before the collision. It is given by :

p=mu+m'u'\\\\p=0.25\times 0.31+0.5\times (-0.22)\\\\p=-0.0325\ kg-m/s

So, the total momentum of the system before the collision is 0.0325 kg-m/s due east direction.            

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3 years ago
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