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3 years ago

A race car was is moving at a constant speed of 35 m/s. A security car was

Physics

1 answer:

Andrej [43]3 years ago

7 0

Answer:

Final speed of security car v = 65 m/s

Explanation:

Given:

Speed of race car u1 = 35m/s

Speed of security car u2 = 5 m/s

Acceleration = 5 m/s²

Find:

Final speed of security car v

Computation:

Assume, they chase S meter

S = u1t + [1/2]at²

S = 35t

S = u2t + [1/2]at²

so,

35t = 5t + [1/2](5)t²

t = 12 s

v = u + at

v = 5 + 5(12)

Final speed of security car v = 65 m/s

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Chemical vapor deposition can be defined as the interaction between a mixture of gases and the surface of a heated substrate, ca

Valentin [98]

Answer: The given statement is true.

Explanation:

When a substrate is exposed to one more more number of volatile substances that react together on the surface of substrate to produce a suitable deposit of a thin non-volatile film is known as chemical vapor deposition.

This type of reaction generally occurs in heat flux.

Therefore, we can conclude that the statement chemical vapor deposition can be defined as the interaction between a mixture of gases and the surface of a heated substrate, causing chemical decomposition of some of the gas constituents and formation of a solid film on the substrate, is true.

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3 years ago

A resistor and an ideal inductor are connected in series to an ideal battery having a constant terminal voltage V 0. (a) At the

dybincka [34]

Answer:

the voltage across the resistor is V= 0

Explanation:

The correct answer is zero.

The answer is zero because the inductor acts as open circuit.

$i= i_0[1-e^{-\frac{t}{\tau} }]$

i_o= maximum current

\tau= L/R= time constant

i= current at any instant

$V= V_0[1-e^{-\frac{t}{\tau} }]$

at t=0 at the moment when contact is made

V=V_o[1-1]

⇒V= 0 V

3 0

3 years ago

Compared to that of a plane on the ground, is Earth’s gravitational pull on a plane 7 miles above Earth approximately the same?

solniwko [45]

Yes. It's approximately the same, but not exactly.

The weight of an object 7 miles above the Earth's surface (the gravitational force on it) is about 0.35% less than it is down on the surface.

8 0

3 years ago

Read 2 more answers

An attractive force of |1N| exists between two charged particles. The magnitude of both charges is the same. If the particles ar

Sever21 [200]

Answer:

A: -2.6 × 10^(-6) C and 2.6 × 10^(-6) C

Explanation:

According to coulombs law, the formula for the force between 2 charged particles is;

F = kq1•q2/r²

Where;

F is Force = |1N|

q1 and q2 are the charges of both particles

k is coulombs constant = 9 × 10^(9) N.m²/C²

r is distance between particles = 0.25

Now, the force |1N| means -1 or +1

Thus;

-1 = 9 × 10^(9) × q1•q2/(0.25)²

1 = 9 × 10^(9) × q1•q2/(0.25)²

Thus;

q1•q2 = -6.94 × 10^(-12)

Or q1•q2 = 6.94 × 10^(-12)

Now, we are told that the magnitude of both charges are the same.

Thus;

q² = 6.94 × 10^(-12)

q = √(6.94 × 10^(-12))

q = 2.6 × 10^(-6) C

Since from earlier, we saw that;

q1•q2 = -6.94 × 10^(-12)

Or q1•q2 = 6.94 × 10^(-12)

Thus means that one of the charges will be negative while the other will be positive.

Thus, the charges are;

-2.6 × 10^(-6) C and 2.6 × 10^(-6) C

6 0

3 years ago

An undersea research chamber is spherical with an external diameter of 5.50 m . The mass of the chamber, when occupied, is 87600

dmitriy555 [2]

Answer:

the buoyant force on the chamber is F = 7000460 N

Explanation:

the buoyant force on the chamber is equal to the weight of the displaced volume of sea water due to the presence of the chamber.

Since the chamber is completely covered by water, it displaces a volume equal to its spherical volume

mass of water displaced = density of seawater * volume displaced

m= d * V , V = 4/3π* Rext³

the buoyant force is the weight of this volume of seawater

F = m * g = d * 4/3π* Rext³ * g

replacing values

F = 1025 kg/m³ * 4/3π * (5.5m)³ * 9.8m/s² = 7000460 N

Note:

when occupied the tension force on the cable is

T = F buoyant - F weight of chamber = 7000460 N - 87600 kg*9.8 m/s² = 6141980 N

4 0

4 years ago