The Solution for the given system of equations is (-2) and
.
The given are linear equations as follow:
y =
+ 3 .. ... ...(1)
and x = -2. .. .... ...(2)
We already know the first part of the solution (x) which is -2. We can find the other part (y) by putting the value of equation (2) in equation (1).
By putting the values of x in equation (1), we get
y =
+ 3
y =
+ 3
Taking the L. C. M of denominators which will be '3', we get:
y = 
y = 
So the second part (y) of the solution of the given equation is
.
Hence, the overall solution to the given system of equation is
.
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T = 5 a
i = 4% aa
j = 1200
c = ...
j = cit/100
c = 100j / it
c = 100*1200 / 4*5
c = 120000 / 20
c = 12000/2
c = 6000
montante
M = c+j
M = 6000+1200
M = 7200