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sleet_krkn [62]
3 years ago
15

On a coordinate plane, a red curved line with an upward arc, labeled g of x, crosses the x-axis at (negative 2, 0), and the y-ax

is at (0, 4). A blue curved line with an upward arc, labeled f of x, crosses the y-axis at (0, 4) and the x-axis at (2, 0). Which statement is true regarding the graphed functions? f(0) = 2 and g(–2) = 0 f(0) = 4 and g(–2) = 4 f(2) = 0 and g(–2) = 0 f(–2) = 0 and g(–2) = 0
Mathematics
2 answers:
frozen [14]3 years ago
8 0

Answer: f(0) = g(0)

Took the quiz

maxonik [38]3 years ago
7 0

Answer:

f(0) = g(0)

Step-by-step explanations

if a function h(x) passes through [a,b] then it can be said that h(a)=b.

given that, g(x) passes through (-2,0) and (0,4)

so, g(-2)=0, g(0)=4.

f(x) passes through (0,4) and (2,0)

so, f(2)=0, f(0)=4.

therefore, f(0)=g(0)=4.

so, first option is correct.

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4 0
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The polynomial of degree 3 , P ( x ) , has a root of multiplicity 2 at x = 2 and a root of multiplicity 1 at x = − 3 . The y -in
lesya [120]

Answer:

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Step-by-step explanation:

<u>We are given</u> :

P ( x ) , has a root of multiplicity 2 at x = 2

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⇔  a  = -0,7

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P ( x ) = -0.7 (x - 2)²(x + 3)

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