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2 years ago

100 points please helpp

Mathematics

1 answer:

Fudgin [204]2 years ago

4 0

Answer:

The answer is J because the line inside the box is at 78

Step-by-step explanation:

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The proportion of items in a population that possess a specific attribute is known to be 0.45. a. If a simple random sample of s

yanalaym [24]

Answer: 0.05

Step-by-step explanation:

Sampling error is the error occurs by considering sample for study instead of entire population.

Given : The proportion of items in a population that possess a specific attribute is known to be 0.45.

Sample size : n= 100

Sample proportion of items in a population that possess a specific attribute : $\hat{p}=0.48$

Now, the formula to find the sampling error :

$\text{Sampling error} =\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$\text{Sampling error} =\sqrt{\dfrac{0.48(1-0.48)}{100}}$

$=\sqrt{\dfrac{0.48(0.52)}{100}}\\\\=\sqrt{0.002496}\approx0.05$

Hence, the sampling error =0.05

4 0

2 years ago

How are repeating decimals used in real-world situations

kumpel [21]

Amount of money and checks could be one...

4 0

3 years ago

Read 2 more answers

The admissions office of a private university released the following admission data for the preceding academic year: From a pool

lina2011 [118]

Answer: Our required probability is 0.1695.

Step-by-step explanation:

Since we have given that

Number of male applicants = 4200

Number of female applicants = 3800

So, total number of applicants = 4200+3800 = 8000

Probability of male entered and subsequently enrolled is given by

$0.4\times 0.4=0.16$

Probability of female entered and subsequently enrolled is given by

$0.4\times 0.45\\\\=0.18$

Number of male entered and subsequently enrolled is given by

$0.16\times 4200\\\\=672$

Number of female entered and subsequently enrolled is given by

$0.18\times 3800\\\\=684$

So, Probability that a student who applied for admission will be accepted by the university and subsequently will enroll is given by

$\dfrac{672+684}{8000}\\\\=\dfrac{1356}{8000}\\\\=0.1695$

Hence, our required probability is 0.1695.

3 0

2 years ago

The scale factor from S to M is 3/2 What is the scale factor from M to S

natita [175]

we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.

<h3></h3><h3>What is the scale factor from M to S?</h3>

Suppose we have a figure S. If we apply a stretch of scale factor K to our figure S, we can say that all the dimensions of figure S are multiplied by K.

So, if S represents the length of a bar, then after the stretch we will get a bar of length M, such that:

M = S*K

If that scale factor is 3/2, then we have the case of the problem:

M = (3/2)*S

We can isolate S in the above relation:

(2/3)*M = S

Now we have an equation (similar to the first one) that says that the scale factor from M to S is 2/3.

Then we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.

If you want to learn more about scale factors:

brainly.com/question/25722260

#SPJ1

3 0

1 year ago

Maria has gotten scores of 75, 77, 81 and 84 (out of a possible 100) on the four midterm examinations for a math class. If each

timofeeve [1]

Answer:

93.63

Therefore, she need to get a minimum of 93.63 out of 100 in the final exam

Step-by-step explanation:

Given;

Each midterm exam = 15% of total grade

Final exam = 40% of total grade

Midterm scores = 75, 77, 81 and 84 (out of a possible 100)

Total midterm score = 75+77+81+84 = 317

To determine the grade of the four midterm exams in the total score;

We need to find the 15% of the midterm score;

= 15% of 317

= 0.15×317

= 47.55 %

To get a minimum score of 85 % of the total score, the amount of the total score to be secured in the final exam is;

Final exam = 85% - 47.55% = 37.45%

Since final exam is 40% of the total score;

It means she need to get 37.45% out of 40% of the final exam.

Converting it to a score of 100;

Final exam score = 37.45/40 × 100

Final exam score = 93.63

Therefore, she need to get a minimum of 93.63 out of 100 in the final exam

3 0

2 years ago