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OlgaM077 [116]
3 years ago
7

An object with a mass of 6.5 kg accelerates 12.3 m/s2 when an unknown force is applied to it. What is the amount of the force?

Physics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

<h2>79.95 kg</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 6.5 × 12.3

We have the final answer as

<h3>79.95 kg</h3>

Hope this helps you

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Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each ot
jolli1 [7]

Answer:

The electric force between them if the pieces of grain are 2 cm apart is 3.15\times 10^{-11}\textrm{ N}.

Explanation:

Given:

Charge on one grain, Q_{1}=6\times 10^{-10}\textrm{ C}

Charge on another grain, Q_{2}=2.3\times 10^{-15}\textrm{ C}

Separation between them, d=2\textrm{ cm}=0.02\textrm{ m}

Electric force acting between two charges Q_{1}\textrm{ and }Q_{2} separated by a distance d is given as:

F_{elec}=\frac{kQ_{1}Q_{2}}{d^2}

Where, k is Coulomb's constant equal to 9\times 10^9\textrm{ }Nm^2/C^2.

Now, plug in all the values and solve for F{elec}.

F{elec}=\frac{9\times 10^9\times 6.0\times 10^{-10}\times 2.3\times 10^{-15}}{(0.02)^2}\\\\F_{elec}=3.15\times 10^{-11}\textrm{ N}

Therefore, the electric force between them if the pieces of grain are 2 cm apart is 3.15\times 10^{-11}\textrm{ N}.

3 0
3 years ago
Which of the the following distance vs time graphs represents an object the is moving at constant non zero velocity
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A graph with a horizontal line
8 0
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Which of the following can be done to demagnetize a permanent magnet?
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Place the permanent magnet into an AC magnetic field and slowly reduce the field to 0 and the magnet will be temporarily demagnetized. 
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A 2.00-kg object traveling east at 20.0 m/s collides with a 3.00-kg object traveling west at 10.0 m/s.
ELEN [110]
Momentum = mass x velocity

Before collision
Momentum 1 = 2 kg x 20 m /s = 40 kg x m/s
Momentum 2 = 3 kg x -10m/s = -30 kg x m/s

After collision
Momentum 1 = 2 kg x -5 m/s = -10 m/s
Momentum 2 = 3 kg x V2 = 3V2

Total momentum before = total momentum after
40 + -30 = -10 + 3V2
V2 = <span>6.67 m/s

Total kinetic energy before
</span><span>= (1/2) [ 2 kg * 20 m/s * 2 + 3 kg * ( -10 m/s) *2 ]
= 550 J
</span>
<span>Total kinetic energy after
</span>= (1/2) [ 2 kg * ( - 5 m/s) * 2 + 3 kg * 6.67 m/s *2 ]
= 91.73 J

Total kinetic energy lost during collision
=<span>550 J - 91.73 J
= 458.27 J</span>

8 0
3 years ago
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The graph shows the production of Fe.
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Cheers.
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3 years ago
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