The answer is false since ionization energy is the amount of energy required to REMOVE the most loosely bound electron
PV = nRT
T
=
PV
nR
=
1.0 atm × 0.5 L
3.5 mol × 0.0821 L atm / (mol K)
=
1.74 K
Answer:
0.453 moles
Explanation:
The balanced equation for the reaction is:
2Fe(s) + 3O2(g) ==> 2Fe2O3
From the equation, mass of O2 involved = 16 x 2 x 3 = 96g
mass of Fe2O3 involved = [(2x26) + 3 x 16] x 2
= 100g
Therefore 96g of O2 produced 100g of Fe2O3
32.2g of O2 Will produce 100x32.2/96
= 33.54g of Fe2O3
Converting it to mole using number of mole = mass/molar mass
but molar mass of Fe2O3 = 26 + (16 X 3)
= 74g/mole
Therefore number of mole of 33.54g of Fe2O3 = 33.54/74
= 0.453 moles
<u>Answer:</u> The wavelength of an electron is ![2.121\times 10^{-11}m](https://tex.z-dn.net/?f=2.121%5Ctimes%2010%5E%7B-11%7Dm)
<u>Explanation:</u>
To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:
![\lambda=\frac{h}{mv}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7Bh%7D%7Bmv%7D)
where,
= De-Broglie's wavelength = ?
h = Planck's constant = ![6.626\times 10^{-34}Js](https://tex.z-dn.net/?f=6.626%5Ctimes%2010%5E%7B-34%7DJs)
m = mass of electron = ![9.109\times 10^{-31}kg](https://tex.z-dn.net/?f=9.109%5Ctimes%2010%5E%7B-31%7Dkg)
v = velocity of electron = ![3.43\times 10^{7}m/s](https://tex.z-dn.net/?f=3.43%5Ctimes%2010%5E%7B7%7Dm%2Fs)
Putting values in above equation, we get:
![\lambda=\frac{6.626\times 10^{-34}Js}{(9.109\times 10^{-31}kg)\times (3.43\times 10^{7}m/s)}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cfrac%7B6.626%5Ctimes%2010%5E%7B-34%7DJs%7D%7B%289.109%5Ctimes%2010%5E%7B-31%7Dkg%29%5Ctimes%20%283.43%5Ctimes%2010%5E%7B7%7Dm%2Fs%29%7D)
![\lambda=2.121\times 10^{-11}m](https://tex.z-dn.net/?f=%5Clambda%3D2.121%5Ctimes%2010%5E%7B-11%7Dm)
Hence, the wavelength of an electron is ![2.121\times 10^{-11}m](https://tex.z-dn.net/?f=2.121%5Ctimes%2010%5E%7B-11%7Dm)