Answer:
C₅ H₁₂ O
Explanation:
44 g of CO₂ contains 12 g of C
30.2 g of CO₂ will contain 12 x 30.2 / 44 = 8.236 g of C .
18 g of H₂O contains 2 g of hydrogen
14.8 g of H₂0 will contain 1.644 g of H .
total compound = 12.1 out of which 8.236 g is C and 1.644 g is H , rest will be O
gram of O = 2.22
moles of C, O, H in the given compound = 8.236 / 12 , 2.22 / 16 , 1.644 / 1
= .6863 , .13875 , 1.644
ratio of their moles = 4.946 : 1 : 11.84
rounding off to digits
ratio = 5 : 1 : 12
empirical formula = C₅ H₁₂ O
Answer:
The answer is...
Explanation:
Smaller crystals have more surface area.
Answer:
The mass of dinitrogen monoxide gas that is collected is 27.6 grams
Explanation:
<u>Step 1:</u> Data given
Molar mass of N2O = 44.013 g/mole
Temperature = 19.0 °C = 292 Kelvin
volume of the gas = 30.0 L
Pressure of the gas = 0.500 atm
Gasconstant = 0.08206 L*atm/K*mol
<u>Step 2</u>: Calculate number of moles
via the ideal gas law:
P*V = n*R*T
n= (P*V)/(R*T)
n= (0.500 atm * 30.0 L)/(0.08206 L*atm/K*mol *292 K)
n =0.626
<u>Step 3:</u> Calculate mass of dinitrogen monoxide
mass = number of moles * Molar mass
mass of N2O = 0.626 moles * 44.013 g/mole
mass of N2O = 27.6 grams
The mass of dinitrogen monoxide gas that is collected is 27.6 grams
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