(a) what are the x and y components of each vector?
For vector v1:
v1 = 6.6 (cos (180) i + sine (180) j)
v1 = 6.6 (-1i + 0j)
v1 = -6.6i
For vector v2:
v2 = 8.5 (cos (55) i + sine (55) j)
v2 = 8.5 ((0.573576436) i + (0.819152044) j)
v2 = 4.88 i + 6.96 j
(b) determine the sum v v 1 2
The sum of both vectors is given by:
v1 + v2 = (-6.6i) + (4.88 i + 6.96 j)
Adding component to component:
v1 + v2 = (-6.6 + 4.88) i + (6.96) j
v1 + v2 = (-1.72) i + (6.96) j
We substitute in c using 9, it will be as follows:
5 ×[(-6×9)+4] = 5 × (-54+4) = 5 × (-50) = -250
Answer:
x = 20
Step-by-step explanation:
The angles shown are alternate exterior angles.
Alternate exterior angles are congruent
This means that 46 must equal 3x - 14
Note that we've just created an equation that we can use to solve for
We now use the equation to solve for x
3x - 14 = 46
add 14 to both sides
3x - 14 + 14 = 46 + 14
simplify
3x = 60
Divide both sides by 3
3x / 3 = x
60 / 3 = 20
We get that x = 20
