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lara31 [8.8K]
3 years ago
7

1. A number is 6 more than the average of, its half, its one-third and its one sixth

Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer:

let no.be x

its half= x/2

its one third= x/3

its one sixth=x/6

atq.....avg of x= x/2+x/3+x/6//3=6x/6//3=x/3

now...x/3+6=x...as the no.is 6 more than its avg

x= 9

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Step-by-step explanation:

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3 years ago
Find the vertical and horizontal asymptote if they exist
tresset_1 [31]

Hello!

Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.

Horizontal asymptotes are determined by:

1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.

3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.

To find the vertical asymptote:

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x = √5 and x = -√5

Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.

To find the horizontal asymptote:

If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.

Therefore, the horizontal asymptote of this function is y = 0.

Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0

7 0
3 years ago
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CaHeK987 [17]
I hope this helps you

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What will be the effect on the graph of y = Ixl if x is replaced with -x?
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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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