To raise 1 kg by 1C, it will take 129 joules.
To raise 0.015 kg by (85-22)C, it will take (129*0.015)*22 = 42.57 joules.
Answer:
-75.35°
Explanation:
Let C be the sum of the two vectors A and B. Hence, we can write the following

but since the vector C is in the -y direction,
= 0 and
= —12 m.
Thus
![B_{x} =-A_{x} =-[-Acos(180-127)]=(8)*cos(53)\\B_{x} =4.81m](https://tex.z-dn.net/?f=B_%7Bx%7D%20%3D-A_%7Bx%7D%20%3D-%5B-Acos%28180-127%29%5D%3D%288%29%2Acos%2853%29%5C%5CB_%7Bx%7D%20%3D4.81m)
similarly, we can determine
by rearranging equation (1)

so the magnitude of B is

Finally, the direction of B can be calculated as follows
Ф=
hence the vector B makes an angle of 75.35 clockwise with + x axis
Elliptical, as shown by most projections
The molecules of a solid vibrate faster so that they spread out to become a liquid hope this helps
Answer:
The kinetic energy of the merry-goround after 3.62 s is 544J
Explanation:
Given :
Weight w = 745 N
Radius r = 1.45 m
Force = 56.3 N
To Find:
The kinetic energy of the merry-go round after 3.62 = ?
Solution:
Step 1: Finding the Mass of merry-go-round


m = 76.02 kg
Step 2: Finding the Moment of Inertia of solid cylinder
Moment of Inertia of solid cylinder I =
Substituting the values
Moment of Inertia of solid cylinder I
=>
=> 
=> 
Step 3: Finding the Torque applied T
Torque applied T =
Substituting the values
T = 
T = 81.635 N.m
Step 4: Finding the Angular acceleration
Angular acceleration ,
Substituting the values,


Step 4: Finding the Final angular velocity
Final angular velocity ,
Substituting the values,


Now KE (100% rotational) after 3.62s is:
KE = 
KE =
KE = 544J