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3 years ago

What is the acceleration? –0.4 m/s2 –0.2 m/s2 0.2 m/s2 0.4 m/s2

Physics

2 answers:

agasfer [191]3 years ago

8 0

Answer:

0.2m/s2

Explanation:

denis23 [38]3 years ago

6 0

We are asked to solve for the acceleration with the given graph in the problem. Let us recall that the formula for acceleration is shown below:
acceleration (a) = (Vf - Vi) / t
in this problem, we need to pick velocity final and initial such as:
Vf = 10 m/s
Vi = 8 m/s
Check the corresponding time, in this case, the time is (40seconds - 30seconds) equivalent to 10 seconds
Solving for the acceleration, we have it:
a = (10 - 8) / 10
a = 2/10
a = 0.2 m/s²

The answer is 0.2 m/s².

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The graph below shows the speed of a car as it drives along a racetrack.

nordsb [41]

Answer:

Average speed = distance/time

From 1 to 9 seconds:

Distance covered = 1 - 0.2 = 0.8 km

Time = 9 - 1 = 8 sec

Average speed = 0.8 km / 8 sec

Average speed = 0.1 km/s .

The average speed for the whole test is 1.6 km / 20 sec = 0.08 km/sec. A graph of speed vs time would average out as a horizontal line at 0.08 km/sec from 1 sec to 21 sec. The area under it would be (0.08 km/s) x (20 sec) = 1.6 km.

Surprise surprise ! The area under a speed/time graph is the distance covered during that time !

In closing, I want to express my gratitude for the gracious bounty of 3 points with which I have been showered. Moreover, the green breadcrust and tepid cloudy water have also been refreshing.

Explanation:

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3 years ago

When object goes under acceleration

lidiya [134]

when object goes under acceleration

c).its velocity always increases

<h3>Additional information:-</h3>

★ Acceleration: Rate of increase in velocity.

★ Velocity: Distance travelled by a body per unit time in given direction is called velocity .

6 0

3 years ago

Read 2 more answers

A mass on a spring with k=88.7 N/m oscillates 15 times in 9.24s. what is the objects mass? unit=kg?

sweet [91]

The mass on the spring is 0.86 kg

Explanation:

The period of a mass-spring system is given by the equation

$T=2\pi \sqrt{\frac{m}{k}}$

where

m is the mass

k is the spring constant

In this problem, we have:

k = 88.7 N/m is the spring constant

The system makes 15 oscillations in 9.24 s: therefore, the period of the system is

$T=\frac{9.24}{15}=0.62 s$

Now we can re-arrange the first equation to solve for the mass:

$m=k(\frac{T}{2\pi})^2=(88.7)(\frac{0.62}{2\pi})^2=0.86 kg$

Learn more about period:

brainly.com/question/5438962

#LearnwithBrainly

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3 years ago

Thalia is drafting a plan to move a large, perfect sphere concrete sculpture that is in front of her office building. Describe t

Marina86 [1]

For the answer to this question,
Thalia must consider the weight of the object and the mass of the sculpture. Weight and mass are different things. She should also consider the time on how long it will take to move it and where she'll move it.

4 0

3 years ago

Read 2 more answers

A perfectly elastic collision occurs between a 15.0-kg mass traveling at 3.50 m/s and a 9.00-kg mass traveling at 2.35 m/s. if t

BaLLatris [955]

Momentum is conserved in a collision. Momentum is mass*velocity, so you can find your answer by calculating initial and final momentums and setting them equal to each other.

15kg * 3.50 m/s + 9kg * 2.35 m/s = 73.65 kg m/s

73.65 = 9 * 2.8 + 15x

solve for x
x= 3.23

The final velocity is 3.23 m/s

5 0

3 years ago