<u>13788 J is required to finish the work.</u>
Explanation:
Given that,
Mass of lawnmower is 20 kg
Force = 30 N
Displacement ( distance moved )= 20m
The force of 30N is applied along the direction of motion and was applied for the whole 20 m.
The formula of work done for one pass is
Substituting the given data into the formula,
W = 459.6 J
Work done for one pass = 459.6J
Now, work done for 30 passes is calculated by multiplying the work done for one pass into 30.
Work is done by the person pushing the mower to finish the work is <u>13788 J</u>.
B. North Pole because it’s pointing at the north pole, and not the others
Answer:
Transform boundaries
Explanation:
I TOOK A TEST ON THIS QUESTION
Answer:
y = 2.76 [m]
Explanation:
We can find the distance of the fall of the apple using the following kinematic equation, we have to emphasize that this is a typical problem of free fall, so the initial speed is zero, then we give the initial data.
t = time = 0,75[s]
g = gravity = 9.81[m/s^2]
v0 = 0
![y = v_{0}*t+0.5*g*t^{2}\\ y=0.5*(9.81)*(0.75)^{2}\\y= 2.76[m]](https://tex.z-dn.net/?f=y%20%3D%20v_%7B0%7D%2At%2B0.5%2Ag%2At%5E%7B2%7D%5C%5C%20y%3D0.5%2A%289.81%29%2A%280.75%29%5E%7B2%7D%5C%5Cy%3D%202.76%5Bm%5D)
Answer:
The height of the water above the hole in the tank is 58 mm
Explanation:
In order to solve this problem we need to draw a sketch of the dimensions that include the input variables of the problem.
Where:
x = 0.579[m]
y = 1.45 [m]
Using the following kinematic equation we can find the time that takes the water to hit the ground, and then with this time, we can find the velocity of the water in the x-component.
It is necessary to clarify the value of each of the respective variables below
y = - 1.45 [m] "It is negative because this point is below the water outlet"
yo = 0
vo = 0 "The velocity is zero because the component of the speed on the Y-axis does not exist"
therefore:
![-1.45=0.5*(-9.81)*t^{2} \\t = \sqrt{\frac{1.45}{0.5*9.81} } \\t = 0.543[s]](https://tex.z-dn.net/?f=-1.45%3D0.5%2A%28-9.81%29%2At%5E%7B2%7D%20%5C%5Ct%20%3D%20%5Csqrt%7B%5Cfrac%7B1.45%7D%7B0.5%2A9.81%7D%20%7D%20%5C%5Ct%20%3D%200.543%5Bs%5D)
The next step is to determine the velocity in component x, knowing the time.
![v=\frac{x}{t} \\v=\frac{0.579}{.543} \\v = 1.06[m/s]](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bx%7D%7Bt%7D%20%5C%5Cv%3D%5Cfrac%7B0.579%7D%7B.543%7D%20%5C%5Cv%20%3D%201.06%5Bm%2Fs%5D)
Now using torricelli's law we can find the elevation.
![v=\sqrt{2*g*h} \\h=\frac{v^{2} }{2*g} \\h=\frac{1.06^{2} }{2*9.81} \\h= 0.057[m] = 57.95[mm]](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B2%2Ag%2Ah%7D%20%5C%5Ch%3D%5Cfrac%7Bv%5E%7B2%7D%20%7D%7B2%2Ag%7D%20%5C%5Ch%3D%5Cfrac%7B1.06%5E%7B2%7D%20%7D%7B2%2A9.81%7D%20%5C%5Ch%3D%200.057%5Bm%5D%20%3D%2057.95%5Bmm%5D)
