Answer:
option D.
Explanation:
The correct answer is option D.
The irony is the figure of speech which represents the contradiction between what is stated and what actually the scenario is.
the statement by the poet does not have any contradictory statements.
The extended metaphor is a part of speech which is used when there is a comparison between two unlike things in the paragraph.
in the given statement of the poem, there is no comparison.
Personification is the part of speech where human quality are given to non-living things.
in the give statement wind in the wire took up the story can be taken as the human quality.
so, the statement part of speech is personification.
Answer:
the frequency is the fundamental and distance is L = ¼ λ
Explanation:
This problem is a phenomenon of resonance between the frequency of the tuning fork and the tube with one end open and the other end closed, in this case at the closed end you have a node and the open end a belly, so the wavelength is the basis is
λ = 4 L
In this case L = 19.4 cm = 0.194 m
let's use the relationship between wave speed and wavelength frequency and
v = λ f
where the frequency is f = 440 Hz
v = 4 L f
let's calculate
v = 4 0.194 440
v = 341.44 m / s
so the frequency is the fundamental and distance is
L = ¼ λ
For the answer to the question above, first find out the gradient.
<span>m = rise/run </span>
<span>=(y2-y1)/(x2-x1) </span>
<span>the x's and y's are the points given: "After three hours, the velocity of the car is 53 km/h. After six hours, the velocity of the car is 62 km/h" </span>
<span>(x1,y1) = (3,53) </span>
<span>(x2,y2) = (6,62) </span>
<span>sub values back into the equation </span>
<span>m = (62-53)/(6-3) </span>
<span>m = 9/3 </span>
<span>m = 3 </span>
<span>now we use a point-slope form to find the the standard form </span>
<span>y-y1 = m(x-x1) </span>
<span>where x1 and y1 are any set of point given </span>
<span>y-53 = 3(x-3) </span>
<span>y-53 = 3x - 9 </span>
<span>y = 3x - 9 + 53 </span>
<span>y = 3x + 44 </span>
<span>y is the velocity of the car, x is the time.
</span>I hope this helps.
Answer :
(a) The initial velocity is, 14.8 m/s
(b) The acceleration is, 
Explanation :
By the 1st equation of motion,
...........(1)
where,
v = final velocity = 0 s
u = initial velocity
t = time = 6.35 s
a = acceleration
The equation 1 will be:
..........(2)
By the 2nd equation of motion,
...........(3)
where,
s = distance = 47 m
Now substitute equation 2 in 3, we get:
By solving the term, we get:
The acceleration is,
Now we have to calculate the initial velocity.
Using equation 2, we gte:
The initial velocity is, 14.8 m/s
