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3 years ago

7

Early on in the story the narrator mentions the sound of wind through the wires strung overhead: "The wind in the wires took up

the story . . ."Taking the plot's rising action at this point into account, which of the following literary devices is the author most likely using?
A.creative license
B.irony
C.extended metaphor
D.personification

1 answer:

miv72 [106K]3 years ago

5 0

Answer:

option D.

Explanation:

The correct answer is option D.

The irony is the figure of speech which represents the contradiction between what is stated and what actually the scenario is.

the statement by the poet does not have any contradictory statements.

The extended metaphor is a part of speech which is used when there is a comparison between two unlike things in the paragraph.

in the given statement of the poem, there is no comparison.

Personification is the part of speech where human quality are given to non-living things.

in the give statement wind in the wire took up the story can be taken as the human quality.

so, the statement part of speech is personification.

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A particle travels along a straight line with a velocity v = (12 - 3t) m/s, where t is in seconds. When t = 1 s, the particle is

Simora [160]

Answer:

(1).The acceleration is -24 m/s²

The total distance is 912 m.

(2). The distance traveled before it stop is 78 m.

Explanation:

Given that,

Velocity = (12-3t^2) m/s

When t = 1 s, the particle is located 10 m to the left of the origin.

We need to calculate the acceleration at t = 4 sec

Using formula of acceleration

$a=\dfrac{dv}{dt}$

Put the value of v

$a=\dfrac{d}{dt}(12-3t^2)$

$a=-6t$

Put the value of t

$a=-6\times4$

$a=-24\ m/s^2$

The displacement from t = 0,t = 10 s, and the distance the particle travels during this time period.

We need to calculate the distance

Using formula of distance

$ds=v\ dt$

$\int_{-10}^{s}=\int_{1}^{t}{v}dt$

Put the value of v

$\int_{-10}^{s}=\int_{1}^{t}{ (12-3t^2)}dt$

$s+10=12t-t^3-11$

$s=12t-t^3-21$

At t = 0,

$s_{t=0}=-21$

At t = 10,

$s_{t=10}=12\times10-10^3-21$

$s_{t=10}=-901$

The displacement is

$\Delta s=-901-(-21)$

$\Delta s=-880\ m$

The distance at t= 2 sec

$s_{t=2}=12\times2-2^3-21$

$s_{t=2}=-5$

The total distance will be,

$s_{T}=(21-5)+(901-5)$

$s_{T}=912\ m$

(2). We need to calculate the distance at 2 sec

Using equation of motion

$s=ut-\dfrac{1}{2}at^2$

Put the value into the formula

$s=27\times 2+\dfrac{1}{2}\times6\times(2)^3$

$s=78\ m$

Hence, (1).The acceleration is -24 m/s²

The total distance is 912 m.

(2). The distance traveled before it stop is 78 m.

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3 years ago

an object is moving forward with a constant velocity. which statement about this object must be true?

love history [14]

Answer:

• Its acceleration is zero

Explanation:

from definition of acceleration:

${ \rm{acceleration = \frac{change \: in \: velocity}{time} }} \\ \\ { \rm{acceleration = \frac{ \delta \: (velocity)}{time} }}$

• since velocity is constant, change in velocity is zero

${ \boxed{ \rm{ \delta \: (velocity) = 0}}}$

• therefore:

${ \rm{acceleration = \frac{0}{time} }} \\ \\ { \boxed{ \tt{acceleration = 0 \: m {s}^{ - 2} }}}$

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3 years ago

Which type of force can be used to kick a soccer ball?

Airida [17]

Answer:

The answer is Friction.

Hope this helps :)

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2 years ago

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The biological roles of complex organic molecules are determined by their shape -- the way atoms and electrons create charge dis

Hatshy [7]

Answer:

a) P_α = exp (-ΔE / kT), b) P_β = 0.145 , d) ΔE = 309.7 meV

Explanation:

The expression for the number of molecules or particles in a given state in Boltzmann's expression

n = n₀ exp (-ΔE / kT)

Where k is the Bolztmann constant and T the absolute temperature

The probability is defined as the number of molecules in a given state over the total number of particles

P = n / n₀ = exp (- ΔE / kT)

Let's apply this expression to our case

a) P_α = n_α / n₀ = exp (-ΔE / kT)

b) the Boltzmann constant

k = 1,381 10⁻²³ J / K (1 eV / 1.6 10⁻¹⁹ J) = 8.63 10⁻⁵ eV / K

kT = 8.63 105 300 = 2,589 10⁻² eV

P_β = exp (- 50 10⁻³ /2.589 10⁻² = exp (-1.931)

P_β = 0.145

c) If the temperature approaches absolute zero, the so-called is very high, so there is no energy to reach the excited state, therefore or all the molecules go to the alpha state

d) For molecules to spend ¼ of the time in this beta there must be ¼ of molecules in this state since the decay is constant.

P_β = ¼ = 0.25

P_β = exp (- ΔE / kT)

ΔE = -kT ln P_β

ΔE = - 2,589 10⁻² ln 0.25

ΔE = 0.3097 eV

ΔE = 309.7 meV

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3 years ago

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Arada [10]

Answer:

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Explanation:

Your mass on the moon should always be the same as any planet you are on (due to law of mass conservation), only your weight be different as gravitational acceleration is different on each planet.

If you weight 150 lbf on Earth, and gravitational acceleration on Earth is 32.174 ft/s2. The your mass on Earth is

m = W / g = 150 / 32.174 = 4.662 slugs

which is also your mass on the moon.

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3 years ago