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3 years ago

An object, initially at rest, is subject to an acceleration of 34 m/s2. How long will it take for that

Physics

2 answers:

SIZIF [17.4K]3 years ago

6 0

Answer:

If it is moving 34 m/s it will take 100 seconds, or 1:40 to reach 3400 meters.

Explanation:

I found this answer by dividing 3400 by 34 and converting seconds to minutes

nevsk [136]3 years ago

6 0

Answer:

14 s

Explanation:

Given:

v₀ = 0 m/s

a = 34 m/s²

Δx = 3400 m

Find: t

Δx = v₀ t + ½ at²

(3400 m) = (0 m/s) t + ½ (34 m/s²) t²

t = 14.1 s

Rounded to two significant figures, it takes 14 seconds.

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An object falls from rest at a rate of 10 m/s / s . How fast was it traveling after 5 seconds of fall?

Vesna [10]

Answer:

$v = u + at \\ v = 10 + 9.81 \times 5 \\ v = 59.05m {s}^{ - 1}$

7 0

2 years ago

A spring of force constant 285.0 N/m and unstretched length 0.230 m is stretched by two forces, pulling in opposite directions a

Kaylis [27]

Answer: W = 0.3853 J, e = 0.052 m

Explanation: Given that,

K =285.0N/M , L = 0.230m , F = 15N , e = ?

F = Ke

15 = 285 × e

e = 15÷ 285

e =0.052 m

e + L = 0.052 + 0.230

= 0.282m ( spring new length )

Work needed to stretch the spring

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3 years ago

As shown in the figure below, a bullet is fired at and passes through a piece of target paper suspended by a massless string. Th

NikAS [45]

Answer:

M = 0.730*m

V = 0.663*v

Explanation:

Data Given:

$v_{bullet, initial} = v\\v_{bullet, final} = 0.516*v\\v_{paper, initial} = 0\\v_{paper, final} = V\\mass_{bullet} = m\\mass_{paper} = M\\Loss Ek = 0.413 Ek$

Conservation of Momentum:

$P_{initial} = P_{final}\\m*v_{i} = m*0.516v_{i} + M*V\\0.484m*v_{i} = M*V .... Eq1$

Energy Balance:

$\frac{1}{2}*m*v^2_{i} = \frac{1}{2}*m*(0.516v_{i})^2 + \frac{1}{2}*M*V^2 + 0.413*\frac{1}{2}*m*v^2_{i}\\\\0.320744*m*v^2_{i} = M*V^2\\\\M = \frac{0.320744*m*v^2_{i} }{V^2} ....... Eq 2$