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ioda
2 years ago
14

Factor f(x) into linear factors given that k is a zero of f(x).

Mathematics
1 answer:
Studentka2010 [4]2 years ago
3 0

Step-by-step explanation:

step 1. if k is a zero then (x - 1) is a factor of 4x^3 + 23x^2 - 34x + 7.

step 2. we "can" use long division but synthetic division is easier!

step 3. 1 4 23 -34 7

4. 4. 27. -7.

4 27. -7. 0 (must get 0)

step 4. so the factors are (x - 1)(4x^2 + 27x - 7).

step 5. please note if you multiply these factors together you will get the original polynomial!

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Which term describes the red curve in the figure below?
EleoNora [17]

Answer:

the answer was circle


Step-by-step explanation:


5 0
3 years ago
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if $6700 is invested at 4.6% interest compounded semiannually, how much will the investment be worth in 15 years???
ella [17]
6700(1+ \frac{4.6}{100} )^{15}

6 0
3 years ago
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the product of five consecutive odd integers is 945 what is the greatest possible value of any of these integers
Troyanec [42]
If 945 is the product of 5 CONSECUTIVE ODD  numbers, let's find the prime factors of 945:

945 = 5 x 7 x 27 , but we need 5 odd numbers:

945= 5 x 7 x ( 3 x 9 ) we still need one factor. This factor cannot be but 1

945 = 1 x 3 x 5 x 7 x 9 = 945 and the greatest value of these integers is 9
4 0
3 years ago
The question in the image.
GREYUIT [131]

Answer:

500 boxes

Step-by-step explanation:

<em>hey there,</em>

<em />

< Since "p" stands for profits, change "p" to 0 (since the question says 0 profits).

Here is how your equation would look like:

0 = -n^2 + 300n + 100000

Pretend like "n" is "x" since that is the variable we are trying to find here.

Solve for "n". Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

"n" actually ends up equaling 500, -200.

Obviously, negative can't be the answer because you can't have a negative amount of boxes. So 500 boxes would be your answer. 200 CAN'T be your answer <em>either </em>because it is a negative!! >

<u>Hope this helped! Feel free to ask anything else.</u>

6 0
3 years ago
How do I do this qn?
denis-greek [22]
You can take the log of the left and right hand side, and then apply the <span>logarithm rules:

log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)

log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)

simplifying by writing log9 = 2log3 and log6 = log2+log3

x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) = 
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)

So 6^x = 4/9
3 0
3 years ago
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