Here's the best answer I can give you, but bear with me.
The second option is incorrect because a class method must have a class identifier not an object identifier. What makes myObject an object identifier is the fact that it was created as an instance of the class MyClass in the constructor in line 5 (MyClass myObject= new MyClass(12.4,20);
The answer here should be MyClass.method2(20); Methods must have a set of parentheses, even if it has nothing inside. The first answer has a class identifier but the SOME_VALUE acts much like the Integer.MAX_VALUE; code which stores a constant value and does not actually perform tasks like most methods.
In short, the answer should be the last one but I hope my explanation cleared some things up for you, even if it was a bit more concept heavy than the question probably intended.
Answer:
The answer is "a1 and a2 is an array of pointers".
Explanation:
In this question, A collection of pointers refers to an array of elements where each pointer array element points to a data array element. In the above-given statement, the two-pointer type array "a1 and a2" is declared that holds the same size "8" elements in the array, and each element points towards the array's first element of the array, therefore, both a1 and a2 are pointer arrays.