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Vladimir79 [104]
3 years ago
13

What is the value of the value below. 4/5+3/5+3.5*5

Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:

18.9

Step-by-step explanation:

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Can somebody please solve this? It's a coordinate thingy
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Answer:

Coordinates involve two points. (x,y)

Too find a pair (coordinate), use the x and y lines on the graph and see where the point falls.

For example

Point A is number <em>1</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>y</em><em> </em><em>axis</em>

<em>number</em><em> </em><em>-</em><em>4</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>x</em><em> </em><em>axis</em>

<em>So</em><em>,</em><em> </em><em>you</em><em> </em><em>would</em><em> </em><em>write</em><em> </em><em>the</em><em> </em><em>coordinate</em><em> </em><em>out</em><em> </em><em>at</em><em> </em>

<em>(</em><em>-</em><em>4</em><em>,</em><em>1</em><em>)</em>

The y axis values are the second point, so after you plot all of letters, use the y axis numbers and number them from least to greatest so you can find the mystery word.

6 0
2 years ago
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Integrate Sec (4x - 1) Tan (4x - 1) Dx ​
Delicious77 [7]

\bf \displaystyle\int~sec(4x-1)tan(4x-1)dx \\\\[-0.35em] ~\dotfill\\\\ sec(4x-1)tan(4x-1)\implies \cfrac{1}{cos(4x-1)}\cdot \cfrac{sin(4x-1)}{cos(4x-1)}\implies \cfrac{sin(4x-1)}{cos^2(4x-1)} \\\\[-0.35em] ~\dotfill\\\\ \displaystyle\int~\cfrac{sin(4x-1)}{cos^2(4x-1)}dx \\\\[-0.35em] ~\dotfill\\\\ u=cos(4x-1)\implies \cfrac{du}{dx}=-sin(4x-1)\cdot 4\implies \cfrac{du}{-4sin(4x-1)}=dx \\\\[-0.35em] ~\dotfill

\bf \displaystyle\int~\cfrac{~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{u^2}\cdot \cfrac{du}{-4~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies -\cfrac{1}{4}\int\cfrac{1}{u^2}du\implies -\cfrac{1}{4}\int u^{-2}du \\\\\\ -\cfrac{1}{4}\cdot \cfrac{u^{-2+1}}{-1}\implies \cfrac{1}{4}\cdot u^{-1}\implies \cfrac{1}{4u}\implies \cfrac{1}{4cos(4x+1)}+C

5 0
3 years ago
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