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Allushta [10]
3 years ago
14

What is the median of this data 10,11,14,10,14,11,15

Mathematics
2 answers:
marta [7]3 years ago
8 0

<h3>Answer-</h3>

I think 11 is the median for the data.

hammer [34]3 years ago
4 0
The median is eleven.
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What fraction of a gallon is 3 pints?
Nitella [24]
<span>There are 8 pints in 1 gallon, so 3 pints is 3/8 of a gallon </span>
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Jayda is running around a track where 3 laps is 5km. She runs 6 laps in 20 min. What is her speed in min per km
zzz [600]

Answer:

2km/m

Step-by-step explanation:

6 laps = 10km

(because 3 x 2 = 6 and double 5km as well)

Distance divide time = speed

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3 0
3 years ago
Please help! <br> Express 35 marks out of 40 as a percentage.
Blizzard [7]

Answer:

\huge\boxed{\sf 87.5 \ \%}

Step-by-step explanation:

35 marks out of 40<u> as a fraction:</u>

35 / 40

<u>As a percentage:</u>

<u></u>\sf \frac{35}{40} * 100 \ \%\\\\0.875 * 100 \ \%\\\\87.5 \ \%\\\\\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
7 0
3 years ago
Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!
il63 [147K]

Answer:

x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

Step-by-step explanation:

w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}

6 0
3 years ago
What is the equation of a line (in slope-intercept form) with a slope of -1 and a y
crimeas [40]

Remember that the slope intercept formula is:

y = mx + b

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b is the y-intercept

What we know:

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Therefore:

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Plug the values of <em>m </em>and <em>b </em>in y = mx + b:

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OR

y = -x + 0.7

OR

y = 0.7 - x

^^^These are all written in slope intercept form but just in different ways

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0
3 years ago
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