The measures of spread include the range, quartiles and the interquartile range, variance and standard deviation. Let's consider each one by one.
<u>Interquartile Range: </u>
Given the Data -> First Quartile = 2, Third Quartile = 5
Interquartile Range = 5 - 2 = 3
<u>Range:</u> 8 - 1 = 7
<u>Variance: </u>
We start by determining the mean,
n = number of numbers in the set
Solving for the sum of squares is a long process, so I will skip over that portion and go right into solving for the variance.
5.3
<u>Standard Deviation</u>
We take the square root of the variance,
2.3
If you are not familiar with variance and standard deviation, just leave it.
Answer:
the answer will be D
Step-by-step explanation:
If you would like to solve 2x + 5y = - 13 and 3x - 4y = -8, you can do this using the following steps:
<span>2x + 5y = -13 /*4
3x - 4y = -8 /*5
</span>_________________
8x + 20y = -52
15x - 20y = -40
_________________
8x + 15x + 20y - 20y = -52 - 40
23x = -92 /23
x = -92 / 23
x = -4
<span>2x + 5y = -13
</span>2 * (-4) + 5y = -13
-8 + 5y = -13
5y = -13 + 8
5y = -5
y = -1
(x, y) = (-4, -1)
The correct result would be D.) <span>(-4, -1).</span>
You need to divide the numerator by the denominator so it should be 8 divided by 9 to turn it into a percent multiply the decimal you get by 100. Hope this helps!
Answer:
Temperature after 12 hours = 25°C
Step-by-step explanation:
Given:
Current tempreture = -23°C
Tempreture incresing rate = 4°C per hour
Total time = 12 hour
Find:
Temperature after 12 hours
Computation:
Temperature after 12 hours = Current tempreture + (Tempreture incresing rate)(Total time)
Temperature after 12 hours = -23 + (4)(12)
Temperature after 12 hours = -23 + 48
Temperature after 12 hours = 25°C
