Answer:
2,000,000 + 800,000 + 90,000 + 7,000 + 900 + 20 + 6
Step-by-step explanation:
The answer in itself is 1/128 and here is the procedure to prove it:
cos(A)*cos(60+A)*cos(60-A) = cos(A)*(cos²60 - sin²A)
<span>= cos(A)*{(1/4) - 1 + cos²A} = cos(A)*(cos²A - 3/4) </span>
<span>= (1/4){4cos^3(A) - 3cos(A)} = (1/4)*cos(3A) </span>
Now we group applying what we see above
<span>cos(12)*cos(48)*cos(72) = </span>
<span>=cos(12)*cos(60-12)*cos(60+12) = (1/4)cos(36) </span>
<span>Similarly, cos(24)*cos(36)*cos(84) = (1/4)cos(72) </span>
<span>Now the given expression is: </span>
<span>= (1/4)cos(36)*(1/4)*cos(72)*cos(60) = </span>
<span>= (1/16)*(1/2)*{(√5 + 1)/4}*{(√5 - 1)/4} [cos(60) = 1/2; </span>
<span>cos(36) = (√5 + 1)/4 and cos(72) = cos(90-18) = </span>
<span>= sin(18) = (√5 - 1)/4] </span>
<span>And we seimplify it and it goes: (1/512)*(5-1) = 1/128</span>
8 pieces of fruit and 3 pears
means she bought 4 apples and 1 cantaluope
Answer:
.
Step-by-step explanation:
We have been given that 
and 
. We are asked to write N as a discrete exponential function of t of the form 
.
Using our given information, we can set an equation as:
Using our given information, we will get:
Substitute the given values:
Switch sides:
Take 11th root of both sides:
![\sqrt[11]{(1+r)^{11}}=\sqrt[11]{1.5476190476190476}](https://tex.z-dn.net/?f=%5Csqrt%5B11%5D%7B%281%2Br%29%5E%7B11%7D%7D%3D%5Csqrt%5B11%5D%7B1.5476190476190476%7D)
Therefore, our required function would be .
The answer to this problem is y= 1/10x + 60, the y-intercept of the function is $60, and the range is {y| y (less than or equal to) 60}
